If an urn has 5 white balls 10 red balls what is the probability that 5 randomly selected balls contain exactly 3 white balls?

Mathematics

1 answer:

kondaur [170]3 years ago

3 0

Answer:

0.15

Step-by-step explanation:

Without Mincing words let us dive straight into the solution to the question above. We are given the following information which is going to aid in solving this particular question.

====> It is given, that there are 5 white balls and 10 red balls. Hence, the number of the total balls = 5 white balls + 10 red balls = 15 balls.

Therefore, the probability that 5 randomly selected balls contain exactly 3 white balls = $\left[\begin{array}{ccc}5\\3\end{array}\right]$ × $\left[\begin{array}{ccc}10\\2&\end{array}\right]$ ÷ $\left[\begin{array}{ccc}15\\3\\\end{array}\right]$ = 450 ÷ 3003 = 0.15

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Delvig [45]

Ok, so IDK if I'm about to do this problem right, but here we go;

so first, lets change these all to decimals (I more of a decimal gal)

3 1/2 = 3.5
3 2/3 = 3.6666 (repeating)
3 3/5 = 3.6
3 3/8 = 3.375

So now, just order them from greatest to least.

3.66666, 3.6, 3.5, 3.375.

Now, change them back to fractions.
3 2/3, 3 3/5, 3 1/2, 3 3/8

So, if I'm correct, the answer is 3 2/3%, 3 3/5%, 3 1/2%, 3 3/8%
Hopefully I solved your problem!

6 0

3 years ago

20k + 5 = 5k + 65 know the answer

Katyanochek1 [597]

Solving for 'k'

20k + 5 = 5k + 65

20k = 5k + 65 -5

20k = 5k + 60

20k - 5k = 60

15k = 60

15k/15 = 60/15

k = 4