Answer:
Step-by-step explanation:
3 envelopes having 2 red card
2 envelopes having 1 red card and 1 black card
1 envelope having 2 black cards
We are given that . An envelope is selected at random and a card is withdrawn and found to be red.
So, No. of ways of envelope having red card = 3+2 = 5
No. of required ways of envelope having 1 red card and 1 black card = 2
So, probability of getting an envelope having 1 red card and 1 black card =
Hence The chance the other card is black is
Answer:
6 hours
Step-by-step explanation:
Answer:
6 hours
Step-by-step explanation:
Firstly, it is important to know where the train that leaves Washington will get after one hour since they didn't start at the same time between noon and 1 is 1 hour.
Speed = distance / time
Distance = speed * time
The distance S = 44 * 1
S= 44m
To determine the time they will pass each other
500(total distance)- 44 ( distance gotten to in 1 hour) - d(the distance it willl pass each other =44* t(time the train will pass each other.
456-d =44t
Second train
d = 32t
Substituting to the equation
456-32t=44t
456=76t
t= 6 hours.
The time they will pass each other is six hours.
Answer:
SinL = 7/25
CosL = 24/25
TanL = 7/24
Step-by-step explanation:
Find the diagram attached.
Using SOH CAH TOA in trigonometry identity to find the sinL, cosL and TanL
Note that the hypotenuse is the longest side = 25
The opposite will be the side facing the acute angle L
Opposite = 7
Adjacent = 24
For SinL
sinL = Opposite/Hypotenuse {SOH}
SinL = 7/25
For cosL:
CosL = Adjacent/Hypotenuse{CAH}
CosL = 24/25
For tanL:
TanL = Opposite/Adjacent {TOA}
TanL = 7/24
Answer:
the first one
Step-by-step explanation:
i did the test and got it right
