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Verizon [17]
3 years ago
6

Witch graph represents the given equation?

Mathematics
1 answer:
schepotkina [342]3 years ago
7 0

Answer:

graph c

y= 3/2 x² +4x-2 would be graphed on the left side of the graph and the vertex would be just a little more than -4

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I also need help with this math problem.
vazorg [7]

Answer:

absolute devlation is

1, 1 + 5+9,4+1, 2+8,1+4,3

Step-by-step explanation:

=4,9

95,5 -> 105 3

have a nice day

8 0
2 years ago
Please help I'm so lost!!!<br><br> Factor. <br><br> 9x2−49y2
pantera1 [17]

Answer:

(3x+7y)(3x−7y)

Step-by-step explanation:

Since both terms are perfect squares, factor using the difference of squares formula, a2−b2=(a+b)(a−b) where a=3x and b=7y

Umm if you need more details just ask.

Hope this helps .-.

4 0
4 years ago
2.85 as a mixed number
WARRIOR [948]
The number 2.85 can be writen using the fraction 285/100 which is equal to 57/20 when reduced to lowest terms.
It is also equal to 2 17/20 when writen as a mixed number.
You can use the following approximate value(s) for this number:57/20 =~ 2 6/7 (if you admit a error of 0.250627%)2.85 =~ 2 5/6 (if you admit a error of -0.584795%)2.85 =~ 3 (if you admit a error of 5.263158%)
3 0
3 years ago
Read 2 more answers
Phyllis invested $11,500, a portion earning a simple interest rate of
Cerrena [4.2K]

Answer:

He invested $8500 with rate 3 1/5%

He invested $3000 with rate 3%

Step-by-step explanation:

* <em>Lets revise the rule of the simple interest</em>

- Simple interest I = PRT, where P in the money invested, R is the

 interest rate and T is the time of investment

- Phyllis invested $11,500

- A portion earning a simple interest rate of 3 1/5% (3.2%) per year

- The rest earning a rate of 3% per year

- After one year the total interest earned on these investments

 was $362.00

- We need to find the amount of money invested in each rate

* Assume that he invested $x with rate 3 1/5% and $y with rate 3%

∵ He invested $11,500 in both rates

∴ x + y = 11,500 ⇒ (1)

∵ He invested $x with 3 1/5%

∵ P = $x

∵ R = 3.2/100 = 0.032

∵ T = 1

∴ I_{1}=x(0.032)(1)

∴ I_{1}=0.032x

∵ He invested $y with 3%

∵ P = $y

∵ R = 3/100 = 0.03

∵ T = 1

∴ I_{2}=y(0.03)(1)

∴ I_{2}=0.03y

∵ The total interest was $362.00

- The total interest = I_{1} + I_{2}

∴ 0.032x + 0.03y = 362.00 ⇒ (2)

<em>We have system of equations</em>

x + y = 11,500 ⇒ (1)

0.032x + 0.03y = 362.00 ⇒ (2)

Multiply equation (1) by -0.03 to eliminate y

-0.03x - 0.03y = 345 ⇒ (3)

Add equations (2) and (3)

0.002x = 17

Divide both sides by 0.002

x = 8500

Substitute the value of x in equation (1)

8500 + y = 11,500

Subtract 8500 from both sides

y = 3000

* He invested $8500 with rate 3 1/5%

* He invested $3000 with rate 3%

7 0
3 years ago
What is 85% of 2500 meters
ladessa [460]
<span>2500*0.85=2125 meters</span>
4 0
3 years ago
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