Answer:
∠BKM= ∠ABK
Therefore AB ║KM (∵ ∠BKM= ∠ABK and lies between AB and KM and BK is the transversal line)
m∠MBK ≅ m∠BKM (Angles opposite to equal side of ΔBMK are equal)
Step-by-step explanation:
Given: BK is an angle bisector of Δ ABC. and line KM intersect BC such that, BM = MK
TO prove: KM ║AB
Now, As given in figure 1,
In Δ ABC, ∠ABK = ∠KBC (∵ BK is angle bisector)
Now in Δ BMK, ∠MBK = ∠BKM (∵ BM = MK and angles opposite to equal sides of a triangle are equal.)
Now ∵ ∠MBK = ∠BKM
and ∠ABK = ∠KBM
∴ ∠BKM= ∠ABK
Therefore AB ║KM (∵ ∠BKM= ∠ABK and BK is the transversal line)
Hence proved.
Answer:
Is this a question about the laws of angle of incidence or is it just coordinates
Step-by-step explanation:
Answer:
Linear Pair:
∠ 1 and ∠ 2
Vertical Angles:
∠ 1 and ∠ 3
Supplementary Angles:
∠ 7 and ∠ 6
Step-by-step explanation:
Linear Pair:
A linear pair of angles is formed when two lines intersect.
Two angles are said to be linear if they are adjacent angles formed by two intersecting lines.
The measure of a straight angle is 180 degrees, so a linear pair of angles must add up to 180 degrees.
Example
∠ 1 and ∠ 2 ∠ 8 and ∠ 5 ,etc
Vertical Angles:
The angles opposite each other when two lines cross.
They are always equal.
Example
∠ 1 and ∠ 3 ∠ 8 and ∠ 6 ,etc
Supplementary Angles:
Two Angles are Supplementary when they add up to 180 degrees.
Examples two angles (140° and 40°)
All Linear pair are Supplementary angles
Example
∠ 7 and ∠ 6 ∠ 8 and ∠ 5 ,etc
Answer:
it is B. -11 and 47
Step-by-step explanation:
you have to take away 47 and 11 and it equals 36.
I don't get what you mean can u pleez give me information what i have to do
