Answer:
5
Step-by-step explanation:
1. Recall the vertical line equation.
2. Plug in the x that we know.
3. Write down the final equation
Pls mark me brainiest :)
1. 2x^2-x-15=0
A = 2
B = -1
C = -15
2. 10^2-2x=0
A = 10
B = -2
C = 0
3. x^2–3x-40=0
A = 1
B = -3
C = -40
4. x^2+3x-2=0
A = 1
B = 3
C = -2
5. 4x^2-17x+8=0
A = 4
B = -17
C = 8
Remember the equations should look like Ax^2+Bx+C=0 (in this order!!)
Name all the angles that have v as a vertex
Ur gonna have to pick an equation and solve for a variable.
2x - 2y = 6
2x = 2y + 6 ...divide everything by 2 because u want x by itself
x = y + 3
now we sub y + 3 in for x in the other equation
14x - 2y = 78
14(y + 3) - 2y = 78...distribute thru the parenthesis
14y + 42 - 2y = 78...subtract 42 from both sides, cancelling the 42 on the left
-42 -42
-----------------------
14y - 2y = 36 ...simplify
12y = 36...divide by 12 on both sides, cancelling out the 12 on the left
y = 36/12
y = 3
now , we already know that x = y + 3...and we know y = 3...so sub in 3 for y and solve for x
x = y + 3
x = 3 + 3
x = 6
solution is (6,3)
it is always a good idea to check ur answer by subbing it into one or both of the equations to see if it is correct
2x - 2y = 6......(6,3)...x = 6 and y = 3
2(6) - 2(3) = 6
12 - 6 = 6
6 = 6 (correct)
so yes, ur solution is (6,3)
