I will suppose that your queation is 10<x<y<14
there are only two odd between 10 and 14
which are 11 and 13
since x is smaller than y
x=11 and y=13
there sum will be x+y=11+13=24
Answer:
xx
Step-by-step explanation:
Answer:
x = 1, y = 3
x = -5, y = -3
Step-by-step explanation:
Point Form:
(1,3) , (-5, -3)
Answer:
21.5 mm^2
Step-by-step explanation:
First find the area of the square
A = s^2 = 10^2 =100
Then find the area of the circle
d = 10 so r = d/2 = 10/2 =5
A = pi r^2
A = 3.14 (5)^2 =78.5
The difference is the shaded region
100-78.5 =21.5
Answer:
B and D
Step-by-step explanation:
