Those are all lines...
So the x interval is from -2 to 3, because of x=-2 and x=3
The upper line is y(u)=4x and the lower line is y(l)=x-5
So the area between the two lines is:
A=⌠y(u)-y(l) dx
A=⌠4x-x+5 dx
A=⌠3x+5 dx
A=[3x^2/2+5x]
A=[(3x^2+10x)/2], x=[-2,3]
A=(1/2)(27+30-(12-20))
A=(1/2)(57+8)
A=(1/2)(65)
A=32.5 u^2
Answer:
22x?
Step-by-step explanation:
is there more to this question? if not its just simple addition and then add "x" at the end
59 cans ... she counting up by 5s so multiply 5 x 10
Answer:
(3+a)
Step-by-step explanation:
3a + a^2
-------------
a
Factor out an a in the numerator
a(3+a)
-------------
a
Cancel like terms
(3+a)