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nordsb [41]
3 years ago
5

For question 6 what is that value of x? For question 7 find m

Mathematics
1 answer:
forsale [732]3 years ago
3 0

(6) Given that in ΔPQR, m∠P = (x+14)°, m∠Q = (6x-12)° and m∠R = (3x+8)°

We need to determine the value of x.

<u>Value of x:</u>

By triangle sum property, we have;

\angle P+\angle Q+\angle R=180^{\circ}

Substituting the values, we get;

x+14+6x-12+3x+8=180

                          10x+10=180

                                  10x=170

                                      x=17

Thus, the value of x is 17

(7) Given that ΔGHI, m∠G = (4x+13)°, m∠H = (8x-52)° and m∠I = (2x+4)°

We need to determine the measure of ∠G

<u>Value of x:</u>

By triangle sum property, we have;

\angle G+\angle H +\angle I=180

Substituting the values, we get;

4x+13+8x-5+2x+4=180

                          14x+12=180

                                  14x=168

                                      x=12

Thus, the value of x is 12.

<u>The measure of ∠G:</u>

Substituting x = 12 in m∠G = (4x+13)°, we get;

m\angle G=(4(12)+13)^{\circ}

m\angle G=(48+13)^{\circ}

m\angle G=61^{\circ}

Thus, the measure of angle G is 61°

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Please answer it quickly the question is below!!! 40 points!!!!
andrew-mc [135]

Answer:

187.5 ft

Step-by-step explanation:

50 ft x 3.75 = 187.5

8 0
3 years ago
A man travels 20 km by car from Town P to Town Q at an average speed of x km/h. He finds that the time of the journey would be s
yuradex [85]

Answer:

x = 20.

Step-by-step explanation:

First, you should remember the relation:

Distance = Speed*Time.

First, we know that a man travels a distance of 20km at a speed of x km/h, in a time T.

We can write this as:

20km = (x km/h)*T

We know that the time is shortened by 12 minutes if the speed is increased by 5km/h

Rewriting these 12 minutes in hours (remember that 60min = 1 hour)

12 min = (12/60) hours = 0.2 hours

Then from this, he can travel the same distance of 20km in a time T minus 0.2 hours if the speed is increased by 5 km/h

We can write this as:

20km = (x + 5 km/h)*(T - 0.2 h)

Then we have a system of two equations, and we want to find the value of x:

20km = (x km/h)*T

20km = (x + 5 km/h)*(T - 0.2 h)

First, we should isolate the variable T in one of the equations, if we isolate it in the first one, we will get:

20km/(x km/h) = T

Replacing that in the other equation we get:

20km = (x + 5 km/h)*(T - 0.2 h)

20km = (x + 5 km/h)*( 20km/(x km/h) - 0.2 h)

Now we can solve this for x.

Removing the units (that we know that are correct) so the math is easier to read, we get:

20 = (x + 5)*(20/x - 0.2)

We only want to solve this for x.

20 = x*20/x - x*0.2 + 5*20/x - 5*0.2

20 = 20 - 0.2*x + 100/x - 1

subtracting 20 in both sides we get:

20 - 20 = 20 - 0.2*x + 100/x - 1 - 20

0 = -0.2*x + 100/x - 1

If we multiply both sides by x we get:

0 = -0.2*x^2 + 100 - x

-0.2*x^2 - x + 100 = 0

This is just a quadratic equation, we can solve it using the Bhaskara's equation, the solutions are:

x = \frac{-(-1) \pm \sqrt{(-1)^2 - 4*(-0.2)*100} }{2*-0.2}  = \frac{1 \pm 9 }{-0.4}

Then the two solutions are:

x = (1 + 9)/-0.4 = -25

x = (1 - 9)/-0.4 = 20

As x is used to represent a speed, the negative solution does not make sense, so we should use the positive one.

x = 20

then the average speed initially is 20 km/h

3 0
2 years ago
Charles has six times as many action figures as ben together the action figures total more than 75 how many does each have
seropon [69]

Answer:

We have been given that Charles has six times as many action figures as Ben

Let Ben has x action figures

So according to question Charles will have 6x.

together the action figures total more than 75

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x>\frac{75}{7}

So Ben will have more than \frac{75}{7} action pictures.

And 6x>6\frac{75}{7}

6x>\frac{450}{7}

Charles will have more than \frac{450}{7}.

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Arturiano [62]
The answer is 26 home slice.
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10. GCF is 3

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