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3 years ago

Find the midpoint of the segment with the following endpoints. (−5,5) and (−10,2)

Mathematics

1 answer:

Nadya [2.5K]3 years ago

7 0

Answer:

(-7, -2)

Step-by-step explanation:

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F(x)=4(x+2)(x+2)-6 in standard form

ollegr [7]

Answer:

4x^2 + 4x -2

Step-by-step explanation:

Use FOIL to solve (x+2) (x+2)

4(x^2 + 4x +4) - 6

4x^2 + 4x -2

8 0

3 years ago

A bakery is filling an order for 180 cupcakes. Jeff has baked and

REY [17]

Answer:

135 cupcakes

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Malika bought 7 new pairs of shoes. Each pair of shoes cost the same amount and was discounted by $21.75.

ikadub [295]

Multiply the amount of the discount by pairs of shoes:

21.75 x 7 = 152.25

Add that to the total she spent:

152.25 + 654.50 = 806.75

Divide the total by pairs of shoes:

806.75/7 = $115.25

The answer is C. $115.25

3 0

3 years ago

In abc above,what is the length of ad

Nezavi [6.7K]

Answer:

Step-by-step explanation:

First calculate BD using sine ratio in Δ BCD and the exact value

sin60° = $\frac{\sqrt{3} }{2}$ , thus

sin60° = $\frac{opposite}{hypotenuse}$ = $\frac{BD}{BC}$ = $\frac{BD}{12}$ = $\frac{\sqrt{3} }{2}$ ( cross- multiply )

2BD = 12 $\sqrt{3}$ ( divide both sides by 2 )

BD = 6 $\sqrt{3}$

-----------------------------------------------------------

Calculate AD using the tangent ratio in Δ ABD and the exact value

tan30° = $\frac{1}{\sqrt{3} }$ , thus

tan30° = $\frac{opposite}{adjacent}$ = $\frac{AD}{BD}$ = $\frac{AD}{6\sqrt{3} }$ = $\frac{1}{\sqrt{3} }$ ( cross- multiply )

$\sqrt{3}$ AD = 6 $\sqrt{3}$ ( divide both sides by $\sqrt{3}$ )

AD = 6 → B

4 0

3 years ago

Define a function f on a set of real numbers as follows: f(x) = 3x − 1 x , for each real number x ≠ 0 Prove that f is one-to-one

dalvyx [7]

Answer with Step-by-step explanation:

We are given that

$f(x)=\frac{3x-1}{x}$

For each real number $x\neq 0$

To prove that f is one -to-one.

Proof:Let $x_1$ and $x_2$ be any nonzero real numbers such that

$f(x_1)=f(x_2)$

By using the definition of f to rewrite the left hand side of this equation

$f(x_1)=\frac{3x_1-1}{x_1}$

Then, by using the definition of f to rewrite the right hand side of this equation of $f(x_1)=f(x_2)$

$f(x_2)=\frac{3x_2-1}{x_2}$

Equating the expression then we get

$\frac{3x_1-1}{x_1}=\frac{3x_2-1}{x_2}$

$3x_1x_2-x_2=3x_2x_1-x_1$

$3x_1x_2-3x_1x_2+x_1=x_2$

$x_1=x_2$

Therefore, f is one-to-one.

6 0

3 years ago