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aleksandrvk [35]
3 years ago
11

Wriye a algebraic expression of 43 less than t

Mathematics
2 answers:
8090 [49]3 years ago
8 0
T-43 would be your answer
fenix001 [56]3 years ago
4 0
This is the simplest expression 
43 < t 

you can make it more complex by putting the same operations  on both sides of the expression 
for example lets multiply (1- t ) on both sides 

(1-t)43 < t(1-t) 

foil both sides and you get 

43-43t<t-t^2 

this is still equal to your original expression 43<t

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2:x and 12:18 a-3, b-4, c-6
nirvana33 [79]

The Corrected Problem is :

2:x and 12:18 identify the value of x that makes each pair of ratios equivalent .

Solution:

If a pair of Ratios are equivalent then we can write

\frac{2}{x}=\frac{12}{18}\\ \\ \text{Simplify we get}\\ \\ 12x=36\\ \\ \text{Divide both the sides by 12 we get}\ \\ \\ \frac{12x}{12}=\frac{36}{12}\\ \\  x=3\\ \\ \text{Hence the required value of x is 3}\\

3 0
3 years ago
Read 2 more answers
Marsha earn $25 per hour up to 36 hours; after this,she is paid double time. In one particular week she earned $1550.00 .how man
mel-nik [20]

Answer: Marta worked 13 hours overtime.

Step-by-step explanation:

1): You do 25 x 36 to get the amount of money she can make before she starts to make double.

36 x 25 = 900

2): Minus $900 from $1550

$1550 - $900 = $650

3): Divide $650 by $50

$650 / $50 = 13 hours worked overtime

7 0
2 years ago
Factor this trinomial completely.
kifflom [539]

Answer:

2 ( x+3) (x+1)

Step-by-step explanation:

2x^2+8x+6

Factor out a 2

2(x^2 +4x+3)

Factor in side the parentheses

What multiply to 3 and adds to 4  (3(1=3  3+1 =4)

2 ( x+3) (x+1)

8 0
3 years ago
After 3 days a sample of radon-222 has decayed to 58% of its original amount.(
iren2701 [21]
Half-life = [elapsed time * log (2)] / [log (begng amt / endg amt)]
half-life =  (3 days * 0.30102999566) / log (1 / .58)
<span>half-life =  0.903089987 / log </span> (<span> <span> <span> 1.724137931)
</span></span></span>half-life =  <span>0.903089987 / 0.23657200643</span>
half-life =  <span> <span> <span> 3.8174 days

Source:
http://www.1728.org/halflife.htm

</span></span></span>
3 0
2 years ago
* Let S = Span {(2,-1, 1), (3, 1, 1), (1, 2, 0)}. (i) Calculate the dimension of S.
Sholpan [36]

The span of 3 vectors can have dimension at most 3, so 9 is certainly not correct.

Check whether the 3 vectors are linearly independent. If they are not, then there is some choice of scalars c_1,c_2,c_3 (not all zero) such that

c_1 (2,-1,1) + c_2 (3,1,1) + c_3 (1,2,0) = (0,0,0)

which leads to the system of linear equations,

\begin{cases} 2c_1 + 3c_2 + c_3 = 0 \\ -c_1 + c_2 + 2c_3 = 0 \\ c_1 + c_2 = 0 \end{cases}

From the third equation, we have c_1=-c_2, and substituting this into the second equation gives

-c_1 + c_2 + 2c_3 = 2c_2 + 2c_3 = 0 \implies c_2 + c_3 = 0 \implies c_2 = -c_3

and in turn, c_1=c_3. Substituting these into the first equation gives

2c_1 + 3c_2 + c_3 = 2c_3 - 3c_3 + c_3 = 0 \implies 0=0

which tells us that any value of c_3 will work. If c_3 = t, then c_1=t and c_2 = -t. Therefore the 3 vectors are not linearly independent, so their span cannot have dimension 3.

Repeating the calculations above while taking only 2 of the given vectors at a time, we see that they are pairwise linearly independent, so the span of each pair has dimension 2. This means the span of all 3 vectors taken at once must be 2.

3 0
1 year ago
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