Answer:
the wire is 24 meters long , rounded to the nearest tenth it's 20 .
Answer:
L1 = 18 cm
W1 = 14 cm
A1 = 252 cm²
Step-by-step explanation:
Since the small rectangle is ½ the scale drawing of the original figure, therefore the dimensions of the smaller rectangle would be half of that of the original.
Thus:
Length (L) of the original = 36 cm
Length (L1) of the smaller rectangle = ½(36) = 18 cm
Width (W) of the original = 28 cm
Length (W1) of the smaller rectangle = ½(28) = 14 cm
Area (A1) of the smaller rectangle = L1 × W1 = 18 × 14 = 252 cm²
Answer:
You didn't provide any choices but.....
Step-by-step explanation:
with N representing the cost of the game
N - .18(N)
<u>Given</u><u> info</u><u>:</u><u>-</u> Find the remainder when x^5 - 3x^3 + x - 5 is divided by x - 2
<u>Solution:</u><u>-</u>
Given,
p(x) = x^5 - 3x^3 + x - 5 , g(x) = x - 2
Let g(x) = x-2 will be the factor of p(x) if p(2) = 0.
Now, p(x) = x^5 - 3x^3 + x - 5
p(2) = (2)^5 - 3(2)^3 + 2 - 5
= (2*2*2*2*2) - 3(2*2*2) + 3 - 5
= 32 - 3(8) + 3 - 5
= 32 - 24 + 3 - 5
= 31 - 24 - 2
= 31 - 26
= 5 Remainder.
Hence, when x^5 - 3x^3 + x - 5 is divided by x - 2 , we get the remainder as 5.
That's a quadratic, a nice parabola in vertex form.
The parabola has a positive x^2 term, so it's a CUP, concave up positive. It will have a minimum at the vertex, which is (2,5). Plot that point.
Now we need a couple of guide points to draw the usual parabola going up from both sides of its vertex. We try x=0 giving (0,9) and see that x=4 also gives 9, (4,9). Plot the parabola through those two points and the vertex and you're done.
