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UNO [17]
3 years ago
13

HELPPPPPPPPPPPPPPPPPPPPPPPP

Mathematics
1 answer:
nlexa [21]3 years ago
4 0
I believe the answer is C, x-3.
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Ummm sooo I’m really confused and it’s due tomorrow please help me
MaRussiya [10]

Answer:

75

Step-by-step explanation:

If the triangles are similar, it means the ratio between the two give sides is the same. As seen from the smaller triangle the ratio of the two top sides would be 16:50 or 8:25.

Since the first side of the bigger triangle (24) is three times 8 (it's ratio side), then the other side must be 3x25 = 75, which maintains the ratio 8:25 between the two sides (24:75).

Hope this helped!

4 0
3 years ago
The number of bacteria after t hours is given by N(t)=250 e^0.15t a) Find the initial number of bacteria and the rate of growth
Art [367]

Answer:

a) N_0=250\; k=0.15

b) 334,858 bacteria

c) 4.67 hours

d) 2 hours

Step-by-step explanation:

a) Initial number of bacteria is the coefficient, that is, 250. And the growth rate is the coefficient besides “t”: 0.15. It’s rate of growth because of its positive sign; when it’s negative, it’s taken as rate of decay.

Another way to see that is the following:

Initial number of bacteria is N(0), which implies t=0. And N(0)=N_0. The process is:

N(t)=250 e^{0.15t}\\N(0)=250 e^{0.15(0)}\\ N_0=250e^{0}\\N_0=250\cdot1\\ N_0=250

b) After 2 days means t=48. So, we just replace and operate:

N(t)=250 e^{0.15t}\\N(48)=250 e^{0.15(48)}\\ N(48)=250e^{7.2}\\N(48)=334,858\;\text{bacteria}

c) N(t_1)=4000; \;t_1=?

N(t)=250 e^{0.15t}\\4000=250 e^{0.15t_1}\\ \dfrac{4000}{250}= e^{0.15t_1}\\16= e^{0.15t_1}\\ \ln{16}= \ln{e^{0.15t_1}} \\  \ln{16}=0.15t_1 \\ \dfrac{\ln{16}}{0.15}=t_1=4.67\approx 5\;h

d) t_2=?\; (N_0→3N_0 \Longrightarrow 250 → 3\cdot250 =750)

N(t)=250 e^{0.15t}\\ 750=250 e^{0.15t_2} \\ \ln{3} =\ln{e^{0.15t_2}}\\ t_2=\dfrac{\ln{3}}{0.15} = 2.99 \approx 3\;h

6 0
3 years ago
Naram-sin wears a horned helmet that is a symbol of _________.
Lisa [10]
Naram-sin wears a horned helment that is a symbol of his divine power.
7 0
3 years ago
Guys I really need help! Please answer ASAP!
Korvikt [17]

Answer:

a)Pipeline Plunge (-1,2)

b)Wonder Wheel (2,-4)

c)Big Coaster (-3,1)

d)(-1,-2)

6 0
2 years ago
A new car is purchased for 18000 dollars. The value of the car depreciates at 13.5% per year. What will the value of the car be,
leonid [27]

Answer:

The value of car after 14 years is  $ 2,363.04

Step-by-step explanation:

Given as :

The price of new car = N = $ 18,000

The rate of depreciation of the value of the car = R = 13.5 % per year

Let The value of car after 14 years = $ x

The time period = 14 years

<u>Now, According to question</u>

The value of car after n years = initial value of car × (1-\dfrac{\textrm rate}{100})^{\textrm Time}

or, $ x = N × (1-\dfrac{\textrm R}{100})^{\textrm n}

or, $ x = $ 18,000 × (1-\dfrac{\textrm 13.5}{100})^{\textrm 14}

Or, $ x = $ 18,000 × (0.865)^{14}

∴  x = $ 18,000 × 0.13128

I.e x = $ 2,363.04

So, The value of car after 14 years =  x = $ 2,363.04

Hence The value of car after 14 years is  $ 2,363.04  Answer

8 0
3 years ago
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