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boyakko [2]
3 years ago
15

I don’t know the answer.

Mathematics
1 answer:
mamaluj [8]3 years ago
6 0

Answer: *C*


Step-by-step explanation:

2x-1+9<=-12

2x+8<=-12

2x<=-12-8

2x<=-20

*X<=-10*


8x-2-2>=12

8x-4>=12

8x>=12+4

8x>=16

*X>=2*

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Nancy needs 4/5 of a foot of ribbon to make a bow and she has 4 feet ribbon how many bows can she make
vlabodo [156]

Answer:

I believe she can make one bow

Step-by-step explanation:

Iso if she has 5 feet of ribbon and only takes four feet of it then that leaves one foot left but if she has a perfect four foot then she can make a ribbon without extra

5 0
3 years ago
What is the answer for x
alexandr402 [8]

Answer:

x = 8.5

Step-by-step explanation:

I got this answer by assuming the triangles were congurent, if they are not, the answer may vary.  

first, make an equation:

x + 8 = 3x - 9

bring 3x to the other side, by subtracting it

-2x + 8 = -9

Subtract 8

-2x = -17

divide by -2

x = 8.5

Then, just sub x into the formulas

5 0
2 years ago
brooke found the equation of the line passing through the points (-7,25) and (-4,13) in slope-intercept form as follows​
Goryan [66]

Answer:

The equation of the line passing through the points (-7,25) and (-4,13) in slope-intercept form is \mathbf{y=-4x-3}

Step-by-step explanation:

Equation of line passing through the points (-7,25) and (-4,13) in slope-intercept form.

The general equation of slope-intercept form is: y=mx+b

First we need to find slope

The formula used for finding slope is: Slope=\frac{y_2-y_1}{x_2-x_1}

We are given: x_1=-7, y_1=25, x_2=-4, y_2=13

Putting values in formula and finding slope

Slope=\frac{y_2-y_1}{x_2-x_1}\\Slope=\frac{13-25}{-4-(-7)}\\Slope=\frac{13-25}{-4+7}\\Slope=\frac{-12}{3}\\Slope=-4

So, slope m= -4

Now finding y-intercept

Using slope m=-4 and point (-7,25) we can find y-intercept

y=mx+b\\25=-4(-7)+b\\25=28+b\\b=25-28\\b=-3

So, y-intercept b =-3

Now, the equation of required line having slope m=-4 and  y-intercept b=-3 is:

y=mx+b\\y=-4x-3

So, the equation of the line passing through the points (-7,25) and (-4,13) in slope-intercept form is \mathbf{y=-4x-3}

3 0
2 years ago
A cylindrical specimen of cold-worked copper has a ductility (%el) of 25%. if its cold-worked radius is 10 mm, what was its radi
loris [4]

The radius of the cylinder before deformation is 7.5mm

<h3>Deformation of an object</h3>

From the given question, we are given that;

cold work radius of the cylinder is 10mm

Ductility = 25%

Determine the radius before deformation

Radius before deformation = (1-  0.5) + 10

Radius before deformation = 0.75 * 10

Radius before deformation = 7.5mm

Hence the radius of the cylinder before deformation is 7.5mm

Learn more on deformation here: brainly.com/question/6417346

5 0
2 years ago
What are the coordinates of P' if P (-5,-4) undergoes a dilation, centered at the origin, with a scale factor of K=2?
Margaret [11]

Answer:

P' = (-10,-8)

Step-by-step explanation:

Given

P = (-5,-4)

k =2

Required

Determine the image P'

P' is calculated by multiplying P and k.

i.e.

P' = P * k

This gives:

P' = (-5,-4) * 2

P' = (-5* 2,-4* 2)

P' = (-10,-8)

<em>Hence, the image P' after dilating P is (-10,-8)</em>

7 0
2 years ago
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