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3 years ago

V/7=5 Solve for v (I need help right now)

Mathematics

2 answers:

Daniel [21]3 years ago

4 0

Answer:

Step-by-step explanation:

5 times 7 is 35 so v divided by 7 is 5

adoni [48]3 years ago

3 0

Answer:

V=35

Step-by-step explanation:

$\frac{V}{7} =5$

Start by multiplying by 7 on both sides:

V=35

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3 years ago

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4 years ago

What is the product of 96.5 x 2.54 ?

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3 years ago

Please help me i really need help please

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3 years ago

A single card is drawn from a standard 52-card deck. Let D be the event that the card drawn is a black card and let F be the eve

tester [92]

Answer:

The indicated probability of $P(D \cup F')=\frac{25}{26}$

Step-by-step explanation:

Probability of an event E to be;

P(E) = $\frac{Number of events within E}{Total number of possible outcomes}$

As per the given condition:

Total number of possible outcomes = 52 cards.

Let the event be D and F as follows;

D : Drawn card is a black card

F : Drawn card is a 10 card.

Then,

From the given condition:

P(D) = $\frac{26}{52}$ [Out of 52 cards, 26 were black] ,

P(F) = $\frac{4}{52}$ [Out of 52 cards, there are four 10 cards]

For any two events A and B we always have;

$P(A \cup B) = P(A)+P(B)-P(A \cap B)$

Now, we have to find the indicated probability:

$P(D \cup F')=P(D)+P(F')-P(D \cap F')$ ......[1]

First find the P(F');

P(F') =1-P(F) = $1-\frac{4}{52} =\frac{52-4}{52} =\frac{48}{52}$

Also, to find $P(D \cap F')$ .

We use the formula :

For any event A and B independent variable.

$P(A \cap B) =P(A) \cdot P(B)$

then;

$P(D \cap F') =P(D) \cdot P(F') = \frac{26}{52} \cdot \frac{48}{52} =\frac{24}{52}$

Now, substitute these in [1];

$P(D \cup F')=\frac{26}{52} +\frac{48}{52} -\frac{24}{52}$ = $\frac{26+48-24}{52} =\frac{50}{52} = \frac{25}{26}$

Therefore, the probability of $P(D \cup F')=\frac{25}{26}$

3 0

3 years ago