You need to make this is all languages if you want help thank you . :)
if y=367
then you need to figure out this:
367=5x+287
so remove 287 from 367
367-287=80
Then divide by 5
80/5=16
so, x=16
Use quadratic formula
if you had ax^2+bx+c=0, then
x=
a=1
b=?
c=34
subsitute
=5+/-3i
=5+/-3i
make 5+/-3 into fraction over 2,(10+/-6i)/2
=(10+/-6i)/2
multiply both sides by 2
=10+/-6i
we conclude that -b=10
b=-10
ok so equaton is
x^2-10x+34
Answer:
6
Step-by-step explanation:
To solve this problem, you simply plug 2 in for x in the equation of f(x):
f(2) = 2 + 4 = 6
Thus, the answer is 6.
Hope this helps!