The function of the area of the square is A(t)=121
Given that The length of a square's sides begins at 0 cm and increases at a constant rate of 11 cm per second. Assume the function f determines the area of the square (in cm2) given several seconds, t since the square began growing and asked to find the function of the area
Lets assume the length of side of square is x
11
⇒x=11t
Area of square=
Area of square={as the length of side is 11t}{varies by time}
Area of square=121
Therefore,The function of the area of the square is A(t)=121
Learn more about The function of the area of the square is A(t)=121
Given that The length of a square's sides begins at 0 cm and increases at a constant rate of 11 cm per second. Assume the function f determines the area of the square (in cm2) given several seconds, t since the square began growing and asked to find the function of the area
Lets assume the length of side of square is x
11
⇒x=11t
Area of square=
Area of square={as the length of side is 11t}{varies by time}
Area of square=121
Therefore,The function of the area of the square is A(t)=121
Learn more about area here:
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n = 15
Step-by-step explanation:
- Step 1: Calculate n by using the law of exponents that a^m × a^n = a^m+n
For 2^-6*2^n=2^9, a = 2, m = -6 and m + n = 9
⇒ -6 + n = 9
⇒ n = 15
- Step 2: Given 2³ × 4³=2^9. Use law of exponents to prove it.
⇒ 2³ × 4³ can also be written as 2³ × (2²)³ = 2³ × 2^6 [This is based on the law of exponents (a^m)^n = (a)^m×n]
⇒ 2³ × 2^6 = 2^ (3 + 6) = 2^9 [Using the law of exponents a^m × a^n = a^m+n]
All you have to do is add 24 to both sides and you will get y. You add 24 so that it will cancel from one side but be added to the other.
The answer is y=17.
Hope this helps!
Y = mx + n
m = Slope
To two lines be perpendicular to each other the slopes need to meet the condition: ma x mb = -1
y = 2x + 5
ma = 2
D: y = -1/2x + 5
mb = -1/2
ma x mb = -1
2 x -1/2 = -1
2/1 x -1/2 = -1
-2/2 = -1
-1 = -1
It's true.
Answer: D.
Answer:
○ C.
Step-by-step explanation:
Wherever the graph intersects the x-axis is considered your zero [x-intercept], therefore you have your answer:
I am joyous to assist you at any time.