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Karolina [17]
3 years ago
11

Mrs. CADY CONSTRUCTS A CUBE WITH 512 MAGNETIC BLOCKS. STUDENTS IN HER TWO CLASSES WILL EACH MAKE AN IDENTICAL CUBE. THERE ARE 28

STUDENTS IN ONE CLASS AND 25 STUDENTS IN THE OTHER CLASS. HOW MANY BLOCKS DOES SHE NEED FOR ALL HER STUDENTS?
Mathematics
1 answer:
Lilit [14]3 years ago
8 0
YOU DON"T HAVE TO YELL

512 PER STUDENT

BASICALLY,
CUBES NEEDED=CUBES PER STUDENT TIMES NUMBER OF STUDENTS

NUMBER OF STUDENTS=28+25=53

CUBES PER STUDENT=512

CUBES NEEDED=512 TIMES 53 EQUALS 27136 CUBES


SHE NEEDS 27136 CUBES FOR ALL HER STUDENTS
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How do I get the answer to this step by step? pls this is a emergency
solong [7]

Answer:

X = 12

Step-by-step explanation:

If the angle depicted on top is the angle for the inside angle in the triangle, we can find x easily. a line is 180 degrees so we can do 180-151 for the right inside angle. that's 29. we can do 5x+3+9x-20+29 = 180. 14x+12=180. 14x = 180-12. 14x = 168. 168/14 = 12

5 0
2 years ago
The water level in a swimming pool decreases from 60 inches to 58.25 inches in one week.
Keith_Richards [23]
I think it’s gonna be A.
8 0
3 years ago
PLEASE HELP ME
stiv31 [10]
Since it's a right triangle you can use the Pythagorean theorem or Trig (Soh Cah Toa).

I'll just use the Pythagorean theorem : a² + b² = c²
a = 9
b = x
c = 18

9² + x² = 18²
81 + x² = 324
x² = 324 - 81
x² = 243
x = √(243)

factor 243 to find a perfect square

x = √(3*81)
x = 9√(3)<u />
5 0
3 years ago
Greg made pudding every weekend. The more times he made pudding, the more practice he gained. The time he took to make the same
VashaNatasha [74]


After Greg makes the pudding 1 time, it takes him f(1)=2(0.8) ^{1}=1.6 hours to make it.

After Greg makes the pudding 2 times, it takes him f(2)=2(0.8) ^{2}=1.28 hours to make it

After Greg makes the pudding 2 times, it takes him f(3)=2(0.8) ^{3}=1.024 hours to make it

so The function is f(x)=2(0.8) ^{x}

Answer: f of x equals 2 multiplied by 0.8 to the power of x
4 0
4 years ago
Can someone help me?
Lana71 [14]

Answer:

I'm not sure from my answer but I'm going to try

A =  { a^2  -  4  = 0 }

A = { a^2  = 0+ 4 }

A = { a^2  = 4}

Take root of both sides

A = {a = 2}

A = {2}

B = { -2, -1, 0, 1, 2}

C = { 1, 2, 3, 4, 5, 6,7}

i) A\B

= {2} \ {-2,-1,0,1,2}

= ⌀ ( "null set" )

ii) (A\B) \C

= ( {2} \ {-2,-1,0,1,2} ) \ C

= ⌀ \ C

= ⌀ \ { 1, 2, 3, 4, 5, 6,7}

= ⌀ ( "null set" )

iii) (A ∪ B) \ C

= ( { 2 } ∪ { -2, -1, 0, 1, 2} ) \ C

= { -2, -1, 0, 1, 2} \C

= { -2, -1, 0, 1, 2} \ { 1, 2, 3, 4, 5, 6,7}

= { -2, -1, 0 }

iv) ( A\B) ∩ ( A\C)

= (  { 2 } \ {-2,-1,0,1,2} ) ∩ ( { 2 } \ { { 1, 2, 3, 4, 5, 6,7} )

= ⌀ ∩ ⌀

= ⌀

v) ( A ∩ B ) \ C

= ( { 2 }  ∩  { -2, -1, 0, 1, 2 } ) \ C

= { 2 } \ { 1, 2, 3, 4, 5, 6, 7 }

= ⌀ "null set"

7 0
3 years ago
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