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Advocard [28]
2 years ago
13

Solve using the quadratic formula. Show all work. Write each solution in simplest form. No decimals.

Mathematics
1 answer:
BabaBlast [244]2 years ago
3 0

Answer:

C

Step-by-step explanation:

We want to solve the equation:

x^2+2x+7=0

Using the quadratic formula. The quadratic formula is given by:

\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

In this case, <em>a</em> = 1, <em>b</em> = 2, and <em>c</em> = 7.

Substitute:

\displaystyle x=\frac{-(2)\pm\sqrt{(2)^2-4(1)(7)}}{2(1)}

Evaluate:

\displaystyle x=\frac{-2\pm\sqrt{-24}}{2}

Simplify the square root:

\sqrt{-24}=\sqrt{4\cdot 6\cdot -1}=\sqrt{4}\cdot\sqrt{6}\cdot\sqrt{-1}=2i\sqrt{6}

Hence:

\displaystyle x=\frac{-2\pm2i\sqrt{6}}{2}

Simplify:

\displaystyle x=-1\pm i\sqrt{6}

Hence, our solutions are:

\displaystyle x=\left\{-1+i\sqrt{6}, -1-i\sqrt{6}\right\}

Our answer is C.

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2 years ago
-4(2x - 5) – (7 – 3x) = 4(x + 3)
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Answer:

x  = 1/9.

Explanation:

-4(2x - 5) – (7 – 3x) = 4(x + 3)

-8x + 20 - 7 + 3x = 4x + 12

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-9x = -1

x = 1/9.

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A triangle with sides 40 feet 50 feet and 60 feet . On a drawing 1 inch equals 10 feet how long are the sides of the triangle on
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2 years ago
3 and 1/13 in simplest form.
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2 years ago
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Write the composite function in the form f(g(x)). [Identify the inner function u = g(x) and the outer function y = f(u).] y = ta
Irina-Kira [14]

Answer:

The inner function is u = \pi x.

The outer function is f(u) = \tan{u}.

\frac{dy}{dx} = y^{\prime} = \sec^{2}(u)*\pi = \pi\sec^{2}{\pi x}

Step-by-step explanation:

The inner function is the one we apply the outer function to.

So

y = \tan{\pi x}

We apply the outer function tangent to \pi x.

So, the inner function is u = \pi x.

The outer function is f(u) = \tan{u}.

The derivative of a compositve function

y = f(u) in which u = g(x) is given by the following function.

y^{\prime} = f^{\prime}(u)*g^{\prime}(x)

So

f(u) = \tan{u}

f^{\prime}(u) = \sec^{2}{u}

u = g(x) = \pi x

g^{\prime}(x) = \pi

So

y^{\prime} = f^{\prime}(u)*g^{\prime}(x)

\frac{dy}{dx} = y^{\prime} = \sec^{2}(u)*\pi = \pi\sec^{2}{\pi x}

7 0
2 years ago
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