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loris [4]
4 years ago
7

Using the Babylonian method find √600 ???????????? √235. how?

Mathematics
1 answer:
podryga [215]4 years ago
4 0

Answer:

With the Babylonian method \sqrt{600} \approx 24.494897 and \sqrt{235} \approx 15.329709.

Step-by-step explanation:

  • To find the square root of 600, do the following:

1. Make an initial guess:  Because \sqrt{576}=24 and \sqrt{625} =25 you can start with x_{0}=24 as your initial guess.

2. Apply the formula:

x_{1}=\frac{(x_{0}+\frac{x}{x_{0}})}{2} where x=600

x_{1}=\frac{(24+\frac{600}{24})}{2}\\x_{1}=24.5

The number x_{1} is a better approximation to \sqrt{600}

3. Iterate until convergence:

For this apply the formula:

x_{n+1}=\frac{(x_{n}+\frac{x}{x_{n}})}{2}

Convergence is achieved when the digits of x_{n+1} and x_{n} agree to as many decimal places as you desire.

x_{2}=\frac{(x_{1}+\frac{x}{x_{1}})}{2}\\x_{2}=\frac{(24.5+\frac{600}{24.5})}{2}\\x_{2}=24.494897

x_{3}=\frac{(x_{2}+\frac{x}{x_{2}})}{2}\\x_{3}=\frac{(24.494897+\frac{600}{24.494897})}{2}\\x_{3}=24.494897\\

Because x_{2} and x_{3} agree to six decimal places. we can say that an estimate for \sqrt{600} \approx 24.494897.

You can compare with the value that WolframAlpha gives you which is \sqrt{600} \approx 24.49489742 you can see that it agrees to six decimal places.

  • To find the square root of 235, do the following:

1. Make an initial guess:  Because \sqrt{225}=15 and \sqrt{256} =16 you can start with x_{0}=15 as your initial guess.

2. Apply the formula:

x_{1}=\frac{(x_{0}+\frac{x}{x_{0}})}{2} where x=235

x_{1}=\frac{(15+\frac{235}{15})}{2}\\x_{1}=\frac{46}{3}

3. Iterate until convergence:

Apply the formula:

x_{n+1}=\frac{(x_{n}+\frac{x}{x_{n}})}{2}

x_{2}=\frac{(x_{1}+\frac{235}{x_{1}})}{2}\\x_{2}=\frac{(\frac{46}{3}+\frac{235}{\frac{46}{3}})}{2} \\x_{2}=15.329710

x_{3}=\frac{(x_{2}+\frac{235}{x_{2}})}{2}\\x_{3}=\frac{(15.329710+\frac{235}{15.329710})}{2} \\x_{3}=15.329709

x_{4}=\frac{(x_{3}+\frac{235}{x_{3}})}{2}\\x_{4}=\frac{(15.329709+\frac{235}{15.329709})}{2} \\x_{3}=15.329709

Because x_{3} and x_{4} agree to six decimal places. We can say that an estimate for \sqrt{235} \approx 15.329709.

WolframAlpha gives you \sqrt{235} \approx 15.329709716

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