Please, next time, please share the graph referred to in the problem statement.
You are comparing f(x)=2 ln x and g(x) = 4 ln x. The two graphs look the same, except that the amplitude (rise) in 4 ln x is exactly twice that in 2 ln x.
Thus, if 2 ln x = 3, 4 ln x = 2(3) = 6.
Answer:
Step-by-step explanation:
W(-4,-10) lies on third quadrant.
M(-12,0) lies on second quadrant or can say in x axis
C(8,3) lies on first quadrant.
K(11,-5) lies on fourth quadrant.
It's saying that both of the shapes are equal to each other. It wants you to compare them so it would be like AB = SR and such
Answer:
Step-by-step explanation:
<h3>to understand this</h3><h3>you need to know about:</h3>
<h3>tips and formulas:</h3>
- the parabola crosses f(x) at (4,0)
- the vertex of the parabola (2,6)
- vertex:(h,k)
- h=-b/2a
- k=f(x)
- vertex form:f(x)=a(x-h)²+k
- standard form:ax²+bx+c
<h3>let's solve:</h3>
the vertex form of the equation is
let's figure out a
since the parabola crosses f(x) at (0,4)
therefore
let's figure out b,c
- we have to substitute the value of a into the vertex form and then simply it to get b and c
therefore
- [tex] \sf \: c = 4[/tex
Answer:
No real solutions.
Step-by-step explanation:
Let's solve your equation step-by-step.
x2−2x+47=0
For this equation: a=1, b=-2, c=47
1x2+−2x+47=0
Step 1: Use quadratic formula with a=1, b=-2, c=47.
x=
−b±√b2−4ac
2a
x=
−(−2)±√(−2)2−4(1)(47)
2(1)
x=
2±√−184
2
Answer:
No real solutions.