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Brilliant_brown [7]
2 years ago
12

What da answer I’d does not say

Mathematics
1 answer:
Norma-Jean [14]2 years ago
8 0
What’s the question?
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Solve in PEMDAS:<br> 3 + [2 + 3 X (6 X 3)]
sladkih [1.3K]
The answer should be 59
3 0
2 years ago
if the mean of A and B is 20 the mean of B and C is 24 and the mean of A,B and C is 18 .what is the mean of A and C​
gizmo_the_mogwai [7]

Answer:

Step-by-step explanation:

5 0
3 years ago
Let X = the number of nonzero digits in a randomly selected 4-digit PIN that has no restriction on the digits. What are the poss
NISA [10]

Answer:

X = {0, 1, 2, 3, 4}

Step-by-step explanation:

If X is the number of nonzero digits in a 4-digit PIN with no restriction on the digits, the pin can have up to 4 nonzero digits.

Let's see some examples:

If the PIN is 0000 then X = 4

If the PIN is 2045 then X = 3

If the PIN is 7546 then X = 0

From the previous examples, we can see that the possible values for X are 0, 1, 2, 3, 4.

Thus X = {0, 1, 2, 3, 4}

4 0
3 years ago
List at least five importance of having self discipline m following protocol during enhanced community quarantine in your respec
Maksim231197 [3]

Answer:

no clue -0- if I knew I would tell you

4 0
2 years ago
F(x)= 2lxl? (graphing absolute values) I'm a little confused.
Vesnalui [34]
I see. Imagine you have f(x)=|x|. It's a V shaped graph.

Now if f(x)=|x|, 2f(x)=2|x|.

Graph Transformation Rule:

af(x), multiply y-coordinates by a.

*Ultimately, you'd still have a V shaped graph in 2f(x)=2|x|, but the y values of all the coordinates in f(x)=|x| would have to be multiplied by 2 giving you 2f(x)=2|x|.
6 0
3 years ago
Read 2 more answers
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