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juin [17]
3 years ago
7

Write an equation in point-slope form of the line that passes through the given point and has the given slope. (3, –8); m = –5

Mathematics
1 answer:
Paraphin [41]3 years ago
7 0

Answer:

y+8=-5(x-3)

Step-by-step explanation:

The formula for point-slope form is y-y1=m(x-x1)

The points for (x1, y1) are (3, -8), meaning that 3 is x1 and -8 is y1.

So, start by writing your equation like this: y--8=m(x-3)

For the equation y--8=m(x-3), the y--8 will change to a + sign because two negatives make a positive, right? So, the equation should now look like this: y+8=m(x-3).

We know that the slope (m) is -5. Plug that into the equation to get this: y+8=-5(x-3)

And there you have it!! The equation is now in point-slope form!!

y+8=-5(x-3) is the final answer!!

Hope that helps you!! Please give me brainliest!!

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Luda [366]

Answer:

The answer is 15 Shirts

Step-by-step explanation:

We want to know what x is going to equal that makes the equation the same.

First, I make the euations equal to each other by substituting the y -->

7x + 50 = 10x + 5

Then, I combine my similar terms --> 45 = 3x

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Evgesh-ka [11]
       2b                     2a
----------------- +  -----------------
   (b+a)^2            (b^2 - a^2)

            2b                     2a
= ----------------- +  -------------------
      (b+a)(b+a)         (b+a)(b-a)

         2b(b - a) +  2a(b + a)
= ------------------------------------
           (b+a)(b+a)(b-a)


         2b^2 - 2ab  +  2ab + 2a^2
= ---------------------------------------
           (b+a)(b+a)(b-a)

         2b^2 + 2a^2
= ------------------------
        (b+a)(b+a)(b-a)

         2(b^2 + a^2)
= ------------------------
        (b+a)^2 (b-a)

Answer:

Numerator:        2(b^2 + a^2)
Denominator:    (b+a)^2 (b-a)
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