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juin [17]
2 years ago
7

Write an equation in point-slope form of the line that passes through the given point and has the given slope. (3, –8); m = –5

Mathematics
1 answer:
Paraphin [41]2 years ago
7 0

Answer:

y+8=-5(x-3)

Step-by-step explanation:

The formula for point-slope form is y-y1=m(x-x1)

The points for (x1, y1) are (3, -8), meaning that 3 is x1 and -8 is y1.

So, start by writing your equation like this: y--8=m(x-3)

For the equation y--8=m(x-3), the y--8 will change to a + sign because two negatives make a positive, right? So, the equation should now look like this: y+8=m(x-3).

We know that the slope (m) is -5. Plug that into the equation to get this: y+8=-5(x-3)

And there you have it!! The equation is now in point-slope form!!

y+8=-5(x-3) is the final answer!!

Hope that helps you!! Please give me brainliest!!

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A researcher computes the definitional formula for SS, and finds that Σ(x − M) = 44. If this is a sample of 12 scores, then what
olga_2 [115]

Answer:

Option B.

Step-by-step explanation:

Given information:

Σ(x − M) = 44

where, M is mean.

Sample size = 12

The computational formula for sample variance is

s^2=\dfrac{\sum (x-M)^2}{N-1}

where, M is sample mean and N is sample size.

Substitute Σ(x − M) = 44 and N=12 in the above formula.

s^2=\dfrac{44}{12-1}

s^2=\dfrac{44}{11}

s^2=4.0

The sample variance is 4.0.

Therefore, the correct option is B.

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3 years ago
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erica [24]
The answer is d) -2x-7
8 0
2 years ago
Need help right way asap
kari74 [83]

Answer:

A is 2 out of 6

Step-by-step explanation:

Probability of him pulling the one with parallel sides is 2/6 because there are only two out of 6 with parallel lines

7 0
1 year ago
Read 2 more answers
P(x) = 5x4 + 7x3 – 2x2 – 3x + c<br> C=
Ghella [55]

Answer:

c=Px−5x4−7x3+2x2+3x

Step-by-step explanation:

Solve for

c

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3 years ago
Some body can help me with a geometric mean maze
Mars2501 [29]

Answer:

See explanation

Step-by-step explanation:

Theorem 1: The length of the altitude to the hypotenuse of a right triangle is the geometric mean of the lengths of the segments of the hypotenuse.

Theorem 2: The length of each leg of a right triangle is the geometric mean of the length of the hypotenuse and the length of the segment of the hypotenuse adjacent to that leg.

1. Start point: By the 1st theorem,

x^2=25\cdot (49-25)=25\cdot 24=5^2\cdot 2^2\cdot 6\Rightarrow x=5\cdot 2\cdot \sqrt{6}=10\sqrt{6}.

2. South-East point from the Start: By the 2nd theorem,

x^2=40\cdot (40+5)=4\cdot 5\cdot 2\cdot 9\cdot 5\Rightarrow x=2\cdot 5\cdot 3\cdot \sqrt{2}=30\sqrt{2}.

3. West point from the previous: By the 2nd theorem,

x^2=(32-20)\cdot 32=4\cdot 3\cdot 16\cdot 2\Rightarrow x=2\cdot 4\cdot \sqrt{6}=8\sqrt{6}.

4. West point from the previous: By the 1st theorem,

9^2=x\cdot 15\Rightarrow x=\dfrac{81}{15}=\dfrac{27}{5}=5.4.

5. West point from the previous: By the 2nd theorem,

10^2=8\cdot (8+x)\Rightarrow 8+x=12.5,\ x=4.5.

6. North point from the previous: By the 1st theorem,

x^2=48\cdot 6=6\cdot 4\cdot 2\cdot 6\Rightarrow x=6\cdot 2\cdot \sqrt{2}=12\sqrt{2}.

7. East point from the previous: By the 2nd theorem,

x^2=22.5\cdot 30=225\cdot 3\Rightarrow x=15\sqrt{3}.

8. North point from the previous: By the 1st theorem,

x^2=7.5\cdot 36=270\Rightarrow x=3\sqrt{30}.

8. West point from the previous: By the 2nd theorem,

x^2=12.5\cdot (12.5+13.5)=12.5\cdot 26=25\cdot 13\Rightarrow x=5\sqrt{13}.

9. North point from the previous: By the 1st theorem,

12^2=x\cdot 30\Rightarrow x=\dfrac{144}{30}=4.8.

101. East point from the previous: By the 1st theorem,

6^2=1.6\cdot (x-1.6)\Rightarrow x-1.6=22.5,\ x=24.1.

11. East point from the previous: By the 2nd theorem,

20^2=32\cdot (32-x)\Rightarrow 32-x=12.5,\ x=19.5.

12. South-east point from the previous: By the 2nd theorem,

18^2=x\cdot 21.6\Rightarrow x=15.

13. North point=The end.

6 0
2 years ago
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