Answer:
Fail to reject the null hypothesis because 0.15>0.05
. There is not convincing evidence that defensive players can bench-press more weight, on average, than offensive players.
Step-by-step explanation:
Since P>a we can not reject the null hypothesis. We cannot conclude the alternative hypothesis in context.
Answer:
315 km
Step-by-step explanation:
If the bus travels at constant speed, then the slope of the distance versus time graph can be calculated by using any two points from this table.
Let's use the points (0.5, 42) and (4.5, 378):
as we move from the first point to the second, t increases by 4 and y increases by 336. Thus, the slope of this graph is
m = rise / run = 336 km / 4 hr = 84 km/hr
then distance traveled = speed times time, or
distance traveled = (84 km/hr)t, where t is the elapsed time.
In 6 hours the bus would travel
( 84 km/hr )(6 hr) = 504 km, or approx. 315 mi
I would assume 1/5 is your answer. As 1/5+1/5+1/5+1/5+1/5 = 5/5 which is 1.
Answer:
Dimensions of the rectangular plot will be 500 ft by 750 ft.
Step-by-step explanation:
Let the length of the rectangular plot = x ft.
and the width of the plot = y ft.
Cost to fence the length at the cost $3.00 per feet = 3x
Cost to fence the width of the cost $2.00 per feet = 2y
Total cost to fence all sides of rectangular plot = 2(3x + 2y)
2(3x + 2y) = 6,000
3x + 2y = 3,000 ----------(1)
3x + 2y = 3000
2y = 3000 - 3x
y = ![\frac{1}{2}[3000-3x]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5B3000-3x%5D)
y = 1500 - 
Now area of the rectangle A = xy square feet
A = x[
]
For maximum area 
A' =
= 0
1500 - 3x = 0
3x = 1500
x = 500 ft
From equation (1),
y = 1500 - 
y = 1500 - 750
y = 750 ft
Therefore, for the maximum area of the rectangular plot will be 500 ft × 750 ft.
two fencing 3(500+500) = $3000
other two fencing 2(750+750) = $3000
The image is black, what’s the question?