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gogolik [260]
3 years ago
13

In the proportion 16 : 20 :: 24 : 40, what is the product of extremes?

Mathematics
1 answer:
mr Goodwill [35]3 years ago
7 0

Answer:

<h2>16×40</h2>

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>
  • proportion
<h3>let's solve:</h3>

16:20::24:40

20×24=16×40

therefore

our product of extremes is

<h3>16×40</h3>

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Answer:

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Step-by-step explanation:

We have the equation:

-3x^2-6x+k=0

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And we want to determine values of <em>k</em> such that the equation will have real, unequal roots.

In order for a quadratic equation to have real, unequal roots, the discriminant must be a real number greater than 0. Therefore:

b^2-4ac>0

Substitute:

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Solve for <em>k: </em>

<em />12k > -36<em />

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So, for all <em>k</em> greater than -3, our quadratic equation will have two real, unequal roots.

Notes:

If <em>k </em>is equal to -3, then we have two equal roots.

And if <em>k</em> is less than -3, then we have two complex roots.

7 0
3 years ago
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sladkih [1.3K]

Answer:

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Step-by-step explanation:

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~

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Step-by-step explanation:

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3 years ago
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