Answer:
- The lowest value of the confidence interval is 0.5262 or 52.62%
- The highest value of the confidence interval is 0.5538 or 55.38%
Step-by-step explanation:
Here you estimate the proportion of people in the population that said did not have children under 18 living at home.It can also be given as a percentage.
The general expression to apply here is;

where ;
p=sample proportion
n=sample size
z*=value of z* from the standard normal distribution for 95% confidence level
Given;
n=5000
<u>Find p</u>
From the question 54% of people chosen said they did not have children under 18 living at home

<u>To calculate the 95% confidence interval, follow the steps below;</u>
- Find the value of z* from the z*-value table
The value of z* from the table is 1.96
- calculate the sample proportion p
The value of p=0.54 as calculated above

Divide the value of p(1-p) with the sample size, n

- Find the square-root of p(1-p)/n

Here multiply the square-root of p(1-p)/n by the z*

The 95% confidence interval for the lower end value is p-margin of error

The 95% confidence interval for the upper end value is p+margin of error

Answer:
h=10.4137931 ..
Explanation: 10.25 +65.25=75.5 . 75.5 divided by 7.25=10.4137931
Answer:
7/12
Step-by-step explanation:
fraction of field is planted potatoes = 1 - sum of fraction of farm planted with maize and beans
sum of fraction of farm planted with maize and beans =


1 - 5/12 = 7/12