Answer:
x > - 8 or x < 2
Step-by-step explanation:
Given
- 8 < 2(x + 4) or - 3x + 4 > x - 4
Solve each part separately
- 8 < 2(x + 4) ← divide both sides by 2
- 4 < x + 4 ( subtract 4 from both sides )
- 8 < x , thus
x > - 8
OR
- 3x + 4 > x - 4 ( subtract x from both sides )
- 4x + 4 > - 4 ( subtract 4 from both sides )
- 4x > - 8
Divide both sides by - 4, reversing the symbol as a result of dividing by a negative quantity
x < 2
Solution is x > - 8 or x < 2
Answer:
Step-by-step explanation:
4x-8y+6=\\2(2x-4y+3)
4y^{2} -2y^{3} =\\2y(2y-y^{2} )
I bet you're doing the Law of Sines right now. If you use the law of sines you find out that angle A is a 90 degree angle. There is only one triangle you can make with these measurements because if you have one angle of 30 and another of 90, the 3rd angle has to be a 60 degree angle. So it is a special right triangle, 30-60-90
