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2 years ago

6

Write the General Form of the equation of the circle centered at (1, 2) with radius 3. PLZZZZZZZZZZZZZ Help

1 answer:

docker41 [41]2 years ago

7 0

Answer:

X^2 +Y^2 - 2X-4Y= 0

Step-by-step explanation:

From the circle eqn.

(x-a) ^2 +(y-b) ^2 =r^2

a=1, b= 2. r= 3

(x-1)^2 +(y-2)^2 =3^2

(x-1)(x-1)+(y-2)(y-2)=3^2

X^2 - 2x+1+y^2 -4y+4=9

X^2 +Y^2 - 2x-4y+5=9

X^2 +Y^2 - 2x-4y-4=0

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Clara has 8 coins worth 17¢. if the coins are all dimes and pennies, how many dimes and pennies does she have?

Sliva [168]

Let x = the number of dimes
Let y = the number of pennies.

There are 8 coins, therefore
x + y = 8 (1)

The coins are worth 17 cents, therefore
10x + y = 17 (2)

Subtract equation (1) from equation (2).
10x + y - (x + y) = 17 - 8
9x = 9
x = 1

From (1), obtain
y = 8 -x = 8 - 1 = 7

Answer: 1 dime, 7 pennies.

4 0

3 years ago

Read 2 more answers

Amy's yearly salary is given by the equation y = 25,000 + 700x, where x is the number of years since 2007 and y is her salary in

yanalaym [24]

2007 would be 0 years since 2007

y=25000+700(0)
y=25000

Answer: Her yearly salary in 2007 was $25,000

Hope this helps:)

3 0

3 years ago

If 900 is shared in the ratio 8:10,find each shared

kirill [66]

Answer:

400 and 500

Step-by-step explanation:

the ratios are 8:10

total ratio = 8+10 = 18

share for the ratio is 8 = 8/18×900

= 0.444444444×900= 400

therefore, share for the ratio of 8= 400

share for the ratio of 10= 10/18×900

= 0.555555555×900=500

therefore, share for the ratio of 10= 500

7 0

1 year ago

The median home value in Torrance is currently $750,900. Last Year the median home price in Torrance was 650,700. What is the pe

Solnce55 [7]

Answer:

15.40(approximately).

Step-by-step explanation:

The current price is $750900.

The last year the price was $650700.

Amount increase in the price is $(750900 - 650700) = $100200.

Hence the percentage is $\frac{100200}{650700} times 100$ = 15.40 (approximately).

5 0

3 years ago

Construct a quadratic polynomial whose zeroes are negatives of the zeroes of the

sp2606 [1]

Given:

The given quadratic polynomial is :

$x^2-x-12$

To find:

The quadratic polynomial whose zeroes are negatives of the zeroes of the given polynomial.

Solution:

We have,

$x^2-x-12$

Equate the polynomial with 0 to find the zeroes.

$x^2-x-12=0$

Splitting the middle term, we get

$x^2-4x+3x-12=0$

$x(x-4)+3(x-4)=0$

$(x+3)(x-4)=0$

$x=-3,4$

The zeroes of the given polynomial are -3 and 4.

The zeroes of a quadratic polynomial are negatives of the zeroes of the given polynomial. So, the zeroes of the required polynomial are 3 and -4.

A quadratic polynomial is defined as:

$x^2-(\text{Sum of zeroes})x+\text{Product of zeroes}$

$x^2-(3+(-4))x+(3)(-4)$

$x^2-(-1)x+(-12)$

$x^2+x-12$

Therefore, the required polynomial is $x^2+x-12$ .

4 0

3 years ago