Write the General Form of the equation of the circle centered at (1, 2) with radius 3. PLZZZZZZZZZZZZZ Help

Mathematics

1 answer:

docker41 [41]3 years ago

7 0

Answer:

X^2 +Y^2 - 2X-4Y= 0

Step-by-step explanation:

From the circle eqn.

(x-a) ^2 +(y-b) ^2 =r^2

a=1, b= 2. r= 3

(x-1)^2 +(y-2)^2 =3^2

(x-1)(x-1)+(y-2)(y-2)=3^2

X^2 - 2x+1+y^2 -4y+4=9

X^2 +Y^2 - 2x-4y+5=9

X^2 +Y^2 - 2x-4y-4=0

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