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2 years ago

A. 5 b. 7 c. 9 d. 11 PLEASE HELPPP I WILL GIVE BRILLIANT!!!

Mathematics

1 answer:

antiseptic1488 [7]2 years ago

4 0

Answer:

B : 7

Step-by-step explanation:

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Simplify: 10 - 2(3+4)*

melomori [17]

Answer: -4

Step-by-step explanation:

8 0

2 years ago

A car travels 45km in an hour. In each of the next two hours, it travels 78km. What is the average speed of the car.

romanna [79]

Answer:

The average speed of car is 67 kilometers per hour.

Step-by-step explanation:

Given that:

Distance travelled in one hour = 45 km

Distance travelled in next 2 hours = 78*2 = 156 km

Total distance = 45+156 = 201

Total time = 1+2 = 3 hours

Average speed of the car = $\frac{Total\ distance}{Total\ time}$

Average speed of the car = $\frac{201}{3}$

Average speed of the car = 67 km/hr

Hence,

The average speed of car is 67 kilometers per hour.

7 0

2 years ago

Suppose n represents an even number for a simplified expression that represents the product of the next two even numbers

Digiron [165]

N+1 x n+2 = whatever that first part means

3 0

3 years ago

Read 2 more answers

Jan is 2/3 of Karyn's age. Jan's age 8 years ago is 2/5 of Katyn's age 4 yeats from now. Jan is how many younger than Karyn?

Elden [556K]

Answer:

12 years younger.

Step-by-step explanation:

Let Jan's age be J and Karyn's age be K.

$J= \frac{2}{3} K$

Jan's age 8 years ago is 2/5 of Karyn's age 4 yeaRs from now.

$J-8 = \frac{2}{5} (K+4)$

=> $(\frac{2}{3} - \frac{2}{5} ) K = \frac{8}{5} + 8$

=> 4K = 48 X 3

=> K= 36.

=> J= 24.

So Jan is 12 years younger.

8 0

2 years ago

A city hosted a music festival that included three concerts. According to the sales database, 28% of the audience attended the f

Vitek1552 [10]

Answer:

$P(X\cap Y\cap Z)=0.05$

Step-by-step explanation:

From the question we are told that:

Percentage of audience in first concert $P(X)=0.28$

Percentage of audience in second concert $P(Y)=0.42$

Percentage of audience in third concert $P(Z)=0.30$

Audience Percentage at at-least one concert $P(X \cup Y \cup Z)=0.80$

Percentage of audience at first & second concert $P(X \cap Y)=0.10$

Percentage of audience in first & third concert $P(X \cap Z)=0.08$

Percentage of audience in second & third concert $P(Y\cap Z)=0.07$

Generally the equation for probability of attending all concerts $P(X\cap Y\cap Z)$ is mathematically given by

$P(X \cup Y \cup Z)=P(X)+P(Y)+P(Z)-P(X \cap Y)-P(X \cap Z)-P(Y\cap Z)+P(X\cap Y\cap Z)$

$P(X\cap Y\cap Z)=P(X \cup Y \cup Z)-P(X)-P(Y)-P(Z)+P(X \cap Y)+P(X \cap Z)+P(Y\cap Z)$

$P(X\cap Y\cap Z)=0.80-0.28-0.42-0.30+0.10+0.80+0.70$

$P(X\cap Y\cap Z)=0.05$

Therefore the probability that a randomly selected audient attended all the concerts

$P(X\cap Y\cap Z)=0.05$

8 0

3 years ago