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3 years ago

7

Find the circumference, rounding your answer to 1d.p.

1 answer:

Rama09 [41]3 years ago

6 0

Answer:

Can't see the attached image

Step-by-step explanation:

Post another question and make sure it has the image on it :)

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Please help me, haha...

sashaice [31]

Yup the answer is C !!

3 0

3 years ago

How do you find the missing height of a triangle?

g100num [7]

Answer:

Use the Pythagorean theorem

Step-by-step explanation:

The pythagorean theorem is $a^{2} +b^{2} =c^{2}$ where a is a height, b is a height, and c is the hypotenuse, which is the longest side of a triangle. For example, if the triangle has two side with lengths of three and four we would put them into the equation to get:

$3^{2} +4^{2} =c^{2}$

Simplify the equation to get:

$9+16=c^2$

Add 16 and 9 to get 25 and take the square root of both sides:

$\sqrt{25} =c$

The sqrt of 25 is 5. Therefore, the length of the hypotenuse, or c, is 5.

8 0

3 years ago

Read 2 more answers

James earns 20 allowance every month and 30 for each a on his report card

Svetach [21]

Answer:

Part A - the independant variable is the monthly allowance, and the dependent amount is the one that he has to get As for in order to receive it.

Part B - y = 30x + 20

Step-by-step explanation:

7 0

3 years ago

-3(x+ 2y) + 5(3x - y) + y2 for x = 6 and y= 2.

Vera_Pavlovna [14]

Answer:

54

Step-by-step explanation:

4 0

3 years ago

Q3: Identify the graph of the equation and write and equation of the translated or rotated graph in general form. (Picture Provi

natta225 [31]

Answer:

b. circle; $2(x')^2+2(y')^2-5x'-5\sqrt{3}y'-6 =0$

Step-by-step explanation:

The given conic has equation;

$x^2-5x+y^2=3$

We complete the square to obtain;

$(x-\frac{5}{2})^2+(y-0)^2=\frac{37}{4}$

This is a circle with center;

$(\frac{5}{2},0)$

This implies that;

$x=\frac{5}{2},y=0$

When the circle is rotated through an angle of $\theta=\frac{\pi}{3}$ ,

The new center is obtained using;

$x'=x\cos(\theta)+y\sin(\theta)$ and $y'=-x\sin(\theta)+y\cos(\theta)$

We plug in the given angle with x and y values to get;

$x'=(\frac{5}{2})\cos(\frac{\pi}{3})+(0)\sin(\frac{\pi}{3})$ and $y'=--(\frac{5}{2})\sin(\frac{\pi}{3})+(0)\cos(\frac{\pi}{3})$

This gives us;

$x'=\frac{5}{4} ,y'=\frac{5\sqrt{3} }{4}$

The equation of the rotated circle is;

$(x'-\frac{5}{4})^2+(y'-\frac{5\sqrt{3} }{4})^2=\frac{37}{4}$

Expand;

$(x')^2+(y')^2-\frac{5\sqrt{3} }{2}y'-\frac{5}{2}x'+\frac{25}{4} =\frac{37}{4}$

Multiply through by 4; to get

$4(x')^2+4(y')^2-10\sqrt{3}y'-10x'+25 =37$

Write in general form;

$4(x')^2+4(y')^2-10x'-10\sqrt{3}y'-12 =0$

Divide through by 2.

$2(x')^2+2(y')^2-5x'-5\sqrt{3}y'-6 =0$

8 0

4 years ago