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3 years ago

For each sentence, write an equation. Solve the equation to find the number

Mathematics

1 answer:

Sholpan [36]3 years ago

6 0

Answer:

a) x=-15

b) x= 27

c) x=14

Step-by-step explanation:

a) x/-3+1=6 x/-3=5 (-3)x/-3=5(-3) x=-15

-1 -1

b) 3-x/9=0 -x/9=-3 (-9) -x/9=-3(-9) x=27

-3 -3

c) x/-2+4=-3 x/-2= -7 (-2)x/-2= -7(-2) x=14

-4 -4

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Seth's homework assignment is to write factor pairs that contain only composite

patriot [66]

Answer:

F. 6 x 22

Step-by-step explanation:

6 has more than two factors ( 1, 6, 2, 3), which makes it a composite number.
22 has more than two factors (1, 22, 2, 11), which makes it a composite number.

Therefore, F is the correct answer.

6 0

2 years ago

What's the answer for this question? (The numbers after the letters are indexes btw) 27a9 x 18b5 x 4c2 Over 18a4 x 12b2 x 2c

zysi [14]

Answer:

$\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c} = \frac{9}{2}a^5b^3c$

Step-by-step explanation:

Given

$\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c}$

Required

Simplify

$\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c}$

Cancel out 18

$\frac{27a^9 * b^5 * 4c^2 }{a^4 * 12b^2 * 2c}$

Divide 4 and 2

$\frac{27a^9 * b^5 * 2c^2 }{a^4 * 12b^2 *c}$

Divide 27 and 12 by 3

$\frac{9a^9 * b^5 * 2c^2 }{a^4 * 4b^2 *c}$

Apply law of indices

$\frac{9a^{9-4} * b^{5-2} * 2c^{2-1} }{4}$

$\frac{9a^5 * b^3 * 2c }{4}$

Divide 2 and 4

$\frac{9a^5 * b^3 * c}{2}$

$\frac{9a^5b^3c}{2}$

Rewrite as:

$\frac{9}{2}a^5b^3c$

Hence:

$\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c} = \frac{9}{2}a^5b^3c$

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2 years ago

Right triangle FHG is shown. The sine of angle F is 0.53. What is the cosine of Angle h ?

g100num [7]

Given:

Given that FGH is a right triangle. The sine of angle F is 0.53.

We need to determine the cosine of angle H.

Cosine of angle H:

Given that the sine of angle F is 0.53

This can be written as,

$sin F=0.53$

Applying the trigonometric ratio, we have;

$\frac{HG}{FH}=0.53$ ----- (1)

Now, we shall determine the value of cosine of angle H.

Let us apply the trigonometric ratio $cos \ \theta=\frac{adj}{hyp}$ , we get;

$cos \ H=\frac{HG}{FH}$ ----- (2)

Substituting the value from equation (1) in equation (2), we get;

$cos \ H=0.53$

Thus, the cosine of angle H is 0.53

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3 years ago

18- 8x = 8 + 3(1 - 3x) Work shown please!

AleksAgata [21]

Answer

7 = -x

Step-by-step explanation:

18- 8x = 8 + 3(1 - 3x)

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18- 8x = 11 - 9x

7- 8x = -9x

7 = -x

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3 years ago

Read 2 more answers