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vitfil [10]
3 years ago
7

True/false: the measure of an arc is equal to the measure of the inscribed angle that intercepts it

Mathematics
1 answer:
anyanavicka [17]3 years ago
8 0

Answer:

true

Step-by-step explanation:

i think 90% sure

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Simplify. (-6x^2 + 2y - 1) + (2x^2-5y + 3) A) -4x^2 + 3y -2 B) -4x^2 - 3y - 2 C) -4x^2 + 3y +2 D) -4x^2 -3y +2
Rasek [7]

Combine like terms

-6x^2+2y + -1 +2x^2 + -5y +3

( -6x^2+2x^2)+(2y-5y)+(-1+3)

= -4x^2+3y+2

Answer : C


I hope that's help !


4 0
3 years ago
What are x- intercepts and y- intercepts
Trava [24]

Answer: x and y intercepts are where the line crosses over the x and y axis.

Step-by-step explanation:

6 0
3 years ago
Nora got an allowance of 50¢ each weekday and 75¢ each weekend altogether how much do they get in:
Furkat [3]
A) > since it is 50c per weekday and 75c each weekend assuming it allows for the 2 days each saturday/sunday.
50c * 5 = $2.50 since there are 5 days in weekdays
75c * 2 = $1.50 since there are 2 days in the weekend
Add $2.50 and $1.50 to get $4.00

b) For 3 school days we know it is a weekday on the school week.
So perform 50c * 3 which gives us <span>$1.50

</span>c) 12 days off from school is 10 weekdays and 1 weekend or 2 days of 75c
So now just do 50c * 10 which is $5.00 and 75c * 2 which is $1.50
Add $5.00 and $1.50 and we get $6.50

d) 4 weeks = 20 weekdays since 5 *4 = 20 and 8 days in each weekend since 2 * 4 = 8
Now that we have the amount of weekdays and weekend days we can multiply.
50c * 20 = $10.00
75c * 4 = $3.00
Add $10.00 and $3.00 to get $13.00 for 4 weeks.

e) We have 1 day of the weekend and 2 weekdays here.
50c * 2 = $1.00
75c * 1 = 75c
<span>$1.00 + 75c = $1.75 in those 3 days listed.
</span>
Add all these together to get your total value.
$4.00 + $1.50 + $6.50 + $13.00 + $1.75 = $26.75

7 0
3 years ago
Which pair of expressions is equivalent?
dlinn [17]

Answer:

B

Step-by-step explanation:

sorry if i am wrong

6 0
3 years ago
Please help a girl outtttt
jeyben [28]

Answer:

bottom of graph will move from (0,0) to point (1,3) after transformation

Step-by-step explanation:

given

original : f(x) = x^{2}

transformed; g(x) = (x-1)^{2} + 3

look at this way g(x) =  (x-h)^{2} + k

if (x-h), h>0, move h units to the right

if k>0, move k units up

the bottom of the graph will be at point (1,3)

3 0
3 years ago
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