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2 years ago

True/false: the measure of an arc is equal to the measure of the inscribed angle that intercepts it

Mathematics

1 answer:

anyanavicka [17]2 years ago

8 0

Answer:

true

Step-by-step explanation:

i think 90% sure

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The temperature has been going down at a constant rate.In 4 hours it went down 12 degrees.Which expression best shows the temper

fomenos

Answer:

t = t₀ - 3n

Step-by-step explanation:

Let t be the temperature and t₀ be the initial temperature of the day

Let n be the number of hours after the initial temperature ( t₀) was registered

Let -3 be the constant of change of temperature ( In 4 hours it went down 12 degrees)

Now, let's write down the expression that shows the temperature change each hour, this way:

t = t₀ - 3n

After 2 hours

t = t₀ - 3 * 2 = t₀ - 6

After 5 hours

t = t₀ - 3 * 5 = t₀ - 15

After 3 hours and 30 minutes

t = t₀ - 3 * 3.5 = t₀ - 10.5

5 0

3 years ago

.......................hi I'm board

konstantin123 [22]

Answer:

yes

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Solve the system of equations. 2x−9y=14 x=−6y+7

ipn [44]

Step-by-step explanation:

$put \: x \: into \: equation \: 1$

$2( - 6y + 7) - 9y = 14$

$- 12y + 14 - 9y = 14$

$- 21y + 14 = 14$

$- 21y = 14 - 14$

$- 21y = 0$

$\frac{ - 21y}{12} = \frac{0}{21}$

$y = 0$

$put \: y = 0 \: into \: equation \: 2$

$x = 6y + 7$

$x = 6(0) + 7$

$x = 0 + 7$

$x = 7$

3 0

2 years ago

Read 2 more answers

The mean amount purchased by a typical customer at Churchill’s Grocery Store is $23.50, with a standard deviation of $5.00. Assu

m_a_m_a [10]

Answer: 0.0170

Step-by-step explanation:

Given : The mean amount purchased by a typical customer at Churchill’s Grocery Store is $23.50, with a standard deviation of $5.00.

i.e. $\mu=23.50$

$\sigma=5$

We assume the distribution of amounts purchased follows the normal distribution.

Sample size : n=50

Let $\overline{x}$ be the sample mean.

Formula : $z=\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}$

Then, the probability that the sample mean is at least $25.00 will be :-

$P(\overline{x}\geq\25.00)=P(\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}\geq\dfrac{25-23.50}{\dfrac{5}{\sqrt{50}}})\\\\=P(z\geq2.12)\\\\=1-P(z$

Hence, the likelihood the sample mean is at least $25.00= 0.0170

5 0

3 years ago

Solve for t 4/3 = t/7

Mumz [18]

Answer:

$\frac{28}{3}=t$

Step-by-step explanation:

$\frac{4}{3}=\frac{t}{7}$

Use cross products to simplify the equation. Multiply the denominator of the second fraction by the numerator of the first fraction, and the denominator of the first fraction by the numerator of the second,

$(4)(7) = (3)(t)$

Simplify,

$28=3t$

Inverse operations,

$\frac{28}{3}=t$

4 0

2 years ago