Answer and Step-by-step explanation:
Let x and y be two positive integers and their sum is 14:
X + y = 14
And the sum of square of this number is:
f = x2 + y2
= x2+ (14 – x)2
Differentiate with respect to x, we get:
F’(x) = [ x2 + (14 – x)2]’ = 0
2x + 2(14-x)(-1) = 0
2x +( 28 – 2x)(-1) = 0
2x – 28 +2x = 0
2x + 2x = 28
4x = 28
X = 7
Hence, y = 14 – x = 14 -7 = 7
Now taking second derivative test:
F”(x) > 0
For x = y = 7,f reaches its maximum value:
(7)2 + (7)2 = 49 + 49
= 98
F at endpoints x Є [ 0, 14]
F(0) = 02 + (14 – 0)2
= 196
F(14) = (14)2 + (14 – 14)2
= 196
Hence the sum of squares of these numbers is minimum when x = y = 7
And maximum when numbers are 0 and 14.
Answer:
they spent 20.3 hours every week watching television!
Step-by-step explanation:
Hope it helped :) please mark brainliest :)
Answer:
Insert the numbers into the equation y=3x-5.
the rule states that in every equation the first number is x.so it will be -6=3(4)-5
-6=12-5
-6=7.
If u want, you can leave your answer like that
Answer:
Step-by-step explanation:
51 / 13 = 3.9231 = 3
51 - (13 x 3) = 12
I think the answer to 14 is J
