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bearhunter [10]
1 year ago
10

The function f(x) = –Two-sevenths (five-thirds)x is reflected over the y-axis to create g(x). Which points represent ordered pai

rs on g(x)? Check all that apply.
Mathematics
1 answer:
Marta_Voda [28]1 year ago
7 0

The values of the function if the function f(x) is reflected over y-axis is  g(x) = 10/21x

<h3>Reflection of coordinates</h3>

Reflection is a transformation technique that changes the position of an object on an xy-plane.

If the function f(x) is reflected over y-axis, the resulting function is y = f(-x). Given the following function;

f(x) = -2/7(5/3)x

This can also be written as;

f(x) = -10/21 x

Replace x as -x

f(-x) = -10/21(-x)

f(-x) = g(x) = 10/21x

Hence the values of the function if the function f(x) is reflected over y-axis is  g(x) = 10/21x

Learn more on reflection here; brainly.com/question/26494295

#SPJ1

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7k÷3=21. What is the value of k?
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How can you write the expression with rationalized denominator? sqrt3 - sqrt6 / sqrt 3 + sqrt 6
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Answer:  2√2 - 3

Explanation:


The expession written properly is:

\frac{ \sqrt{3}- \sqrt{6}  }{ \sqrt{3}+ \sqrt{6} }

To rationalize that kind of expressions, this is to eliminate the radicals on the denominator you use conjugate rationalization.

That is, you have to multiply both numerator and denominator times the conjugate of the denominator.

The conjugate of √3+√6 is √3 - √6, so let's do it:

\frac{ \sqrt{3} - \sqrt{6} }{ \sqrt{3} + \sqrt{6} } . \frac{ \sqrt{3}- \sqrt{6}  }{ \sqrt{3}- \sqrt{6} }

To help you with the solution of that expression, I will show each part.

1) Numerator: (√3 - √6) . (√3 - √6) = (√3 - √6)^2 = (√3)^2 - 2√3√6 + (√6)^2 =

= 3 - 2√18 + 6 = 9 - 6√2.

2) Denominator: (√3 + √6).(√3 - √6) = (√3)^2 - (√6)^2 = 3 - 6 = - 3

3) Then the resulting expression is:

 9 - 6√2
-----------
 -3

Which can be further simplified, dividing by - 3

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Answer: 2√2 - 3

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