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3 years ago

Solve for m: -5(m - 3) + 6 = 2(m - 5)

Mathematics

1 answer:

tensa zangetsu [6.8K]3 years ago

4 0

Answer:

Step-by-step explanation:

-5(m - 3) + 6 = 2(m - 5)

<u>Expand the terms in the bracket</u>

That's

- 5m + 15 + 6 = 2m - 10

- 5m + 21 = 2m - 10

<u>Subtract 2m from both sides</u>

- 5m - 2m + 21 = 2m - 2m - 10

- 7m + 21 = - 10

<u>Subtract 21 from both sides</u>

That's

- 7m + 21 - 21 = - 10 - 31

- 7m = - 31

<u>Divide both sides by - 7</u>

We have the final answer as

Hope this helps you

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Martina runs 6 miles in 50 minutes. At the same rate, how many miles would she run in 35 minutes?

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It may be 45 I think

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2 years ago

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△klm, lm=20 sqrt 3 m∠k=105°, m∠m=30° find: kl and km

Anarel [89]

Answer:

KL = $\frac{20\sqrt{6}}{1+\sqrt{3}}$ = 17.93

MK = $\frac{40\sqrt{3}}{1+\sqrt{3}}$ = 25.36

Explanation:

According to the Law of Sines:

$\frac{a}{sinA}=\frac{b}{sinB}= \frac{c}{sinC}$

where:

A, B, and C are angles

a, b, and c are the sides opposite to the angles

First of all, let's find m∠L: the sum of the angles of a triangle is 180°, therefore

m∠K + m∠L + m∠M = 180°

m∠L = 180° - m∠K - m∠M

m∠L = 180° - 105° - 30°

m∠L = 45°

Now, we can apply the Law of Sines to our case (see picture attached):

$\frac{LM}{sinK}=\frac{MK}{sinL}=\frac{KL}{sinM}$

Let's solve one side at the time:

$\frac{LM}{sinK}=\frac{MK}{sinL}$

$\frac{20\sqrt{3}}{sin(105)}=\frac{MK}{sin(45)}$

$MK = \frac{20\sqrt{3} }{sin(105)} \cdot sin(45)$

MK = $\frac{40\sqrt{3} }{1+\sqrt{3} }$ = 25.36

Similarily:

$\frac{LM}{sinK}=\frac{KL}{sinM}$

$\frac{20\sqrt{3}}{sin(105)}=\frac{KL}{sin(30)}$

$KL = \frac{20\sqrt{3} }{sin(105)} \cdot sin(30)$

KL = $\frac{20\sqrt{6}}{1+\sqrt{3}}$ = 17.93

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2 years ago

What is the result of isolating y^2 in the equation below (x-2)^2+y^2=64?

natta225 [31]

What is the result of isolating y^2 in the equation below (x-2)^2+y^2=64?

Solution:

We want to isolate $y^{2}$ from the equation $(x-2)^{2} +y^{2} =64$

To isolate $y^{2}$ , we must try to get $y^{2}$ alone

So, We must subtract $(x-2)^{2}$ from both sides

$(x-2)^{2}-(x-2)^{2} +y^{2} =64-(x-2)^{2}$

$0 +y^{2} =64-(x-2)^{2}$

$y^{2} =64-(x^{2}-4x+4)$

Distributing '-' inside parenthesis

$y^{2} =64-x^{2} +4x -4$

$y^{2} =60-x^{2} +4x$

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2 years ago

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Joshua can purchase tile at one store for $0.99 per tile but he he will have to rent a tile saw for $25. At another store he can

Debora [2.8K]

Answer:

The number of tile for which the cost is same route to nearest tile is 49 .

Step-by-step explanation:

Given as :

The cost which Joshua will pay for tile at one store = $ 0.99 per tile + $ 25 for tile saw

The cost which Joshua will pay for tile at another store = $ 1.50 per tile only

Let The number of tile for which the cost is same route to nearest tile = n

So, According to question

$ 0.99 × number of tile + $ 25 = $ 1.50 × number of tile

or, $ 0.99 × n + $ 25 = $ 1.50 × n

or, $ 1.50 × n - $ 0.99 × n = $ 25

I.e 0.51 × n = $ 25

∴ n = $\frac{25}{0.51}$

I.e n = 49.01 ≈ 49

So, The number of tile for which the cost is same route to nearest tile = n = 49

Hence The number of tile for which the cost is same route to nearest tile is 49 . Answer

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How do I find miles per hour when I get minutes and miles

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In this case you have:

$\frac{miles}{minute}$

An hour has sixty minutes.

$\frac{60 minutes}{1 hour}$

<span>You must multiply by this equality.

</span> $(\frac{miles}{minute})(\frac{60 minutes}{1 hour})=\frac{(miles)(60 minutes)}{ (minute)(hour)}=\frac{(miles)(60)}{(hour)}$

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