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Grace [21]
3 years ago
9

HI PLS HELP!!! A student scored 83 and 91 on their first two quizzes. Write and solve a compound inequality to find the possible

values for a third quiz score that would give them an average between 85 and 90, inclusive.
Mathematics
2 answers:
skelet666 [1.2K]3 years ago
4 0
(Not my answer, stolen)

GenaCL600 [577]3 years ago
4 0

Answer:

between 81 and 96 inclusive

Step-by-step explanation:

well the average of 3 scores is

something / 3

so we have

85\leq \frac{83+91+x}{3}\leq 90

now solving it

85(3)\leq 174+x\leq90(3)\\\\255\leq 174+x\leq 270\\\\81\leq x \leq 96

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3) What is 2/15 + 3/10 ? (hint: find the LCD first)<br> ​
tamaranim1 [39]

Answer:

13/30

Step-by-step explanation:

2/15 x 2 = 4/30

3/10 x 3 = 9/30

4/30 + 9/30 = 13/30

4 0
3 years ago
Read 2 more answers
Josie read 246 pages of a book last month her older brother says he read about 3 to 4 times as many pages as Josie explain why 2
Lubov Fominskaja [6]

Answer:

2500 is not a reasonable estimate.

Step-by-step explanation:

We are given the following in the question:

Number of pages read by Josie = 246

Pages read by older brother = 3 to 4 times as many pages as Josie

If x represents the number of pages read by her brother, we can write:

3(\text{Pages read by Josie})\leq x \leq 4(\text{Pages read by Josie})

Putting values, we get,

3(246) \leq x \leq 4(246)\\738 \leq x \leq 984

Since, 2500 does not lie in this interval

738 \leq 2500 \nleq 984

Thus, 2500 is not a reasonable estimate for the number of pages that Josie's brother read.

8 0
3 years ago
Which of the following tables represent the relationship in the diagram
denis-greek [22]

1 rectangle perimeter =  8 +8 +5 +5 = 26

2 rectangle perimeter = 8 +8 +10+10 = 36

3 rectangle perimeter = 8 +8 +15+15 = 46



3rd table is correct

5 0
3 years ago
The radius of a circle is 13 in. Find its area in terms of <br> π<br><br><br> Please help
Sunny_sXe [5.5K]

Answer: 169π in. squared

Step-by-step explanation: 13x13xπ

3 0
3 years ago
4.Is it sometimes, always, or never true that, if A and B both have dimensions n x n , AB=BA ? Explain.
REY [17]

Answer: Is true sometimes.

Step-by-step explanation:

I guess that here we have two matrices, A and B, that are nxn.

We can see that if those matrices can conmutate, then we can try it with some simple matrices.

A = \left[\begin{array}{ccc}1&0\\0&-1\end{array}\right] . B =  \left[\begin{array}{ccc}2&0\\1&1\end{array}\right]

Here, we would have that:

AB =  \left[\begin{array}{ccc}2&0\\-1&-1\end{array}\right]

BA =  \left[\begin{array}{ccc}2&0\\1&-1\end{array}\right]

You can see that AB and BA are different, then the statement is not always true.

But it is true sometimes, if A or B are the identiti, then I*A = A*I, in this case would be true.

It is also true if A and B are diagonal matrices, let's prove it:

A =  \left[\begin{array}{ccc}a&0\\0&b\end{array}\right] , B =  \left[\begin{array}{ccc}c&0\\0&d\end{array}\right]

AB =  \left[\begin{array}{ccc}ac&0\\0&bd\end{array}\right] = BA

5 0
4 years ago
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