A. Product of a constant factor 12 and two-term factor x+3
From the problem :
In multiplying expressions with the same bases, the exponent will be added accordingly.
For example :
the exponent of a are m and n, and the product will be a raised to the sum of m and n.
Applying this to the problem, we have :
The answer is d. 6^-1
Answer:
Step-by-step explanation:
j=k+4
k=3r
j=3r+4
j+k+r=46
3r+4+3r+r=46
7r+4=46
7r=42
r=6, since k=3r
k=18, since j=k+4
j=22
j,k,r=22,18,6
Answer:
$755.80
Step-by-step explanation:
Determine the compound amount first and then subtract the principal from it, to find the amount of interest.
The compound amount formula is A = P (1 + r/n)^(nt), where
P is the initial principal, r is the interest rate as a decimal fraction, n is the number of compounding periods per year, and t is the number of years. Here, P = $2179; t = 5 yrs; r = 0.06; and n = 4 (quarterly compounding).
We get:
A = $2179(1 + 0.06/4)^(4*5), or $2179(1.015)^20, or $2179(1.347) = $2937.80.
The compound amount is $2934.80. Subtracting the $2179 principal results in the interest earned: $755.80.
