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3 years ago

What is x over 5 - 68 = -95

1 answer:

5 0

Hello, there!

This would look like: x/5 - 68 = -95

First, we want to isolate the x.

x/5 - 68 = -95
+68 +68

x/5 = -27

Now, we will work backwards to find the x.

-27 * 5 = x

-27 * 5 = -135

x = -135

Your answer is -135

I hope I helped!

Let me know if you need anything else!

~ Zoe

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Batteries come in packs of 4. Last month, Joe used 58 batteries in his remote control drone. How many packs of batteries did he

vovangra [49]

It is given that batteries come in a packs of 4. It means in each pack there are 4 batteries.

Joe used 58 batteries . So to find the total number of packets of batteries joe has to open is

Number of batteries used / Total number of batteries in each packet

= 58 / 4

= 14.5

The number of battery can not be in decimal. So we will round the answer to integer. If we round it to 14 it means 14 packets. But in 14 packets there are 14*4 = 56 batteries .

But we know that Joe used 58 batteries. So we will round the final answer to 15.

It means Joe has to open 15 packets of batteries.

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3 years ago

Find the 1st , 2nd (median) and 3rd quartile of the set of numbers 6,8,2,6,7,9 ?

zubka84 [21]

Answer:

at first we put the numbers in order from least to greatest

2 , 6 , 6 , 7 , 8 , 9

1st quartile = 6

median = (6+7)/2 = 6.5

3rd quartile = 8

5 0

3 years ago

EXPLAIN why we placed the value of x= 4/3( the minimum value) into the equ of gradient(dy/dx) [in the answer, marking scheme att

aliina [53]

$y=x(x-2)^2$
$\implies y'=(x-2)^2+2x(x-2)=3x^2-8x+4=(3x-2)(x-2)=0$
$\implies x=\dfrac23,x=2$

are the critical points, and judging by the picture alone, you must have $b=\dfrac23$ and $a=2$ . (You might want to verify with the derivative test in case that's expected.)

Then the shaded region has area

$\displaystyle\int_0^2x(x-2)^2\,\mathrm dx=\dfrac43$

I'll leave the details to you.

Now, for part (iv), you're asked to find the minimum of $\dfrac{\mathrm dy}{\mathrm dx}=y'$ , which entails first finding the second derivative:

$y'=3x^2-8x+4$
$\implies y''=6x-8$

setting equal to 0 and finding the critical point:

$6x-8=0\implies x=\dfrac86=\dfrac43$

This is to say the minimum value of $\dfrac{\mathrm dy}{\mathrm dx}$ *occurs when $x=\dfrac43$ *, but this is not necessarily the same as saying that $\dfrac43$ is the actual minimum value.

The minimum value of $\dfrac{\mathrm dy}{\mathrm dx}$ is obtained by evaluating the derivative at this critical point:

$m=\dfrac{\mathrm dy}{\mathrm dx}\bigg|_{x=4/3}=3\left(\dfrac43\right)^2-8\left(\dfrac43\right)+4=-\dfrac43$

4 0

4 years ago

Can someone help with this please?

Tanzania [10]

Answer:

n=5 and it's output is -13

Step-by-step explanation:

By inspection, the inputs increase by +1 and the outputs decrease by 2

Thus ,n=4+1=5 and it's output is -11-2=-13

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3 years ago

Name three decimals with a product that is about 40.

pochemuha

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3 years ago

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