This can be solve by using the average cans of each student
collected and muliply it by the total students. Since for ms. Lee has 24
students and each student collected 18 cans on average, so the total can her
class collected on average is 432 cans. For mr galveshas 21 students and
collected 25 can per syudents on average, so the total is 525 cans. So 525 –
432 = 93 more cans the class of mr galvez collected
Answer:
your speed is 8.1
Step-by-step explanation:
17.5-9.4=8.1
Answer:
1 5/154
Step-by-step explanation:
Answer:
Smax = 676 ft
the maximum altitude (height) the rocket will attain during its flight is 676 ft
Step-by-step explanation:
Given;
The height function S(t) of the rocket as;
S(t) = -16t2 + 208t
The maximum altitude Smax, will occur at dS/dt = 0
differentiating S(t);
dS/dt = -32t + 208 = 0
-32t +208 = 0
32t = 208
t = 208/32
t = 6.5 seconds.
The maximum altitude Smax is;
Substituting t = 6.5 s
Smax = -16(6.5)^2 + 208(6.5)
Smax = 676 ft
the maximum altitude (height) the rocket will attain during its flight is 676 ft
If we multiply the bottom equation by 2 and move x to the right, it becomes:
4y = 2x-38
Now we can substitute it for the 4y in the top equation:
3x + (2x-38) = -23 => 5x = -23+38 => 5x = 15 => x=3
Then 4y = 2*3-38 => y = -8
So the solution is (3,-8)
