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elena-s [515]
3 years ago
14

Order of operation with Integers

Mathematics
1 answer:
vovikov84 [41]3 years ago
5 0

Answer:

8

Step-by-step explanation:

<em>we have to follow PEDMAS.</em>

<u>what we have to do in each operation:</u>

Parenthesis ~  100 + 8 to the second power

Exponents ~ 10 to the 2nd power, 8 to the 2nd power, 2 to the 3rd power

Multiplication  ~  none

Division ~  10 to the 2nd power - (100 + 8 to the second power) divided by 2 to the 3rd power

Addition ~ 100 + 8 to the 2nd power

Subtraction ~ 10 to the 2nd power - (100+8 to the second power)

<u>doing the work:</u>

we start with P: but in what we have to do in the Parenthesis, there is an exponent and addition. we do the exponent first. 8 to the second power is 64. now we can add. 100 + 64 = 164.

E: we did the 2nd exponent, but we need the other 2 for later. 10 to the 2nd power is 100, and 2 to the 3rd power is 8.

we can skip M because there isn't any multiplication to do.

D: we have to do 10 to the 2nd power - (100 + 8 to the second power) first. 100-164= 64. now we can devide. 64 devided by 8 = 8

A: we already did the addition in the parenthesis part.

S: we already did the addition in the parenthesis part.

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Answer:

The nth term is 109-9n

Step-by-step explanation:

Here, we want to find the nth term of the given arithmetic sequence

Mathematically, we have the nth term as;

Tn = a + (n-1)d

where a is the first term which is 100 in this case

d is the common difference which is the value obtained by subtracting the preceding term from the succeeding term; it is constant throughout the sequence

The value here is thus;

82-91 = 91-100 = -9

Substituting these values

Tn = 100 + (n-1)-9

Tn = 100 -9n + 9

Tn = 100 + 9 - 9n

Tn = 109-9n

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3 years ago
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skelet666 [1.2K]
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Step-by-step explanation:

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3 years ago
Find the length of the tangent segment AB to the circles centered at O and O' whose radii are a and b respectively when the circ
bixtya [17]

Answer:

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Step-by-step explanation:

From figure,

OA=a,  \quad \quad O'B=b\\\Rightarrow OO'= (a+b) \quad \quad \text{and}\quad OD=(a-b)

In triangle OO'D

  (OO')^2=(OD)^2+(O' D)^2

\Rightarrow (a+b)^2=(a-b)^2+(O' D)^2\\\Rightarrow a^2+b^2+2ab-a^2-b^2+2ab=(O' D)^2\\\Rightarrow 4ab=(O' D)^2\\\Rightarrow O'D=2\sqrt{ab} \\\Rightarrow O' D=2\sqrt{ab}=AB \quad \quad [\because O' DAB\;\; \text{is a rectangle.}]

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3 years ago
In the figure shown, ABC is a right triangle with side lengths a, b, and c, and CD is an altitude to side AB. The side lengths o
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Answer:

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Step-by-step explanation:

In the figure shown, ABC is a right triangle with side lengths a, b, and c, and CD is an altitude to side AB. This altitude divides the triangle into two right triangles ADC and BDC. In these triangles,

  • \angle CBD\cong \angle ACD\cong \angle CBA
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So,

\triangle ABC\sim \triangle CBD\sim \triangle ACD

1. From the similarity \triangle ABC\sim \triangle CBD, you have

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2. From the similarity \triangle ABC\sim \triangle ACD, you have

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Hence, option A is true

5 0
3 years ago
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