Find the length of the tangent segment AB to the circles centered at O and O' whose radii are a and b respectively when the circ
les touch each other
1 answer:
Answer:
Step-by-step explanation:
From figure,
In triangle 
![\Rightarrow (a+b)^2=(a-b)^2+(O' D)^2\\\Rightarrow a^2+b^2+2ab-a^2-b^2+2ab=(O' D)^2\\\Rightarrow 4ab=(O' D)^2\\\Rightarrow O'D=2\sqrt{ab} \\\Rightarrow O' D=2\sqrt{ab}=AB \quad \quad [\because O' DAB\;\; \text{is a rectangle.}]](https://tex.z-dn.net/?f=%5CRightarrow%20%28a%2Bb%29%5E2%3D%28a-b%29%5E2%2B%28O%27%20D%29%5E2%5C%5C%5CRightarrow%20a%5E2%2Bb%5E2%2B2ab-a%5E2-b%5E2%2B2ab%3D%28O%27%20D%29%5E2%5C%5C%5CRightarrow%204ab%3D%28O%27%20D%29%5E2%5C%5C%5CRightarrow%20O%27D%3D2%5Csqrt%7Bab%7D%20%5C%5C%5CRightarrow%20O%27%20D%3D2%5Csqrt%7Bab%7D%3DAB%20%5Cquad%20%5Cquad%20%5B%5Cbecause%20O%27%20DAB%5C%3B%5C%3B%20%5Ctext%7Bis%20a%20rectangle.%7D%5D)
Hence,
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The change is 580 feet per hour.
11049 - 7569 is 3480.
Then 3480 ÷ 6 is 580.
<span>(-3,5) (-5,6)
slope = 5-6 / -3 --5
</span><span>slope = -1 / 2
</span>
![\large\begin{array}{l} \textsf{a) }\mathsf{(f\circ g)(x)}\\\\ =\mathsf{f\big[g(x)\big]}\\\\ =\mathsf{\big[g(x)\big]^2-6\cdot g(x)+2}\\\\ =\mathsf{\big[\sqrt{x}\big]^2-6\sqrt{x}+2}\\\\\\ \therefore~~\boxed{\begin{array}{c}\mathsf{(f\circ g)(x)=x-6\sqrt{x}+2} \end{array}}\qquad\checkmark \end{array}](https://tex.z-dn.net/?f=%5Clarge%5Cbegin%7Barray%7D%7Bl%7D%20%5Ctextsf%7Ba%29%20%7D%5Cmathsf%7B%28f%5Ccirc%20g%29%28x%29%7D%5C%5C%5C%5C%20%3D%5Cmathsf%7Bf%5Cbig%5Bg%28x%29%5Cbig%5D%7D%5C%5C%5C%5C%20%3D%5Cmathsf%7B%5Cbig%5Bg%28x%29%5Cbig%5D%5E2-6%5Ccdot%20g%28x%29%2B2%7D%5C%5C%5C%5C%20%3D%5Cmathsf%7B%5Cbig%5B%5Csqrt%7Bx%7D%5Cbig%5D%5E2-6%5Csqrt%7Bx%7D%2B2%7D%5C%5C%5C%5C%5C%5C%20%5Ctherefore~~%5Cboxed%7B%5Cbegin%7Barray%7D%7Bc%7D%5Cmathsf%7B%28f%5Ccirc%20g%29%28x%29%3Dx-6%5Csqrt%7Bx%7D%2B2%7D%20%5Cend%7Barray%7D%7D%5Cqquad%5Ccheckmark%20%5Cend%7Barray%7D)
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![\large\begin{array}{l} \textsf{b) }\mathsf{(g\circ f)(-2)}\\\\ =\mathsf{g\big[f(-2)\big]}\\\\ =\mathsf{\sqrt{f(-2)}}\\\\ =\mathsf{\sqrt{(-2)^2-6\cdot (-2)+2}}\\\\ =\mathsf{\sqrt{4+12+2}}\\\\ =\mathsf{\sqrt{18}}\\\\ =\mathsf{\sqrt{3^2\cdot 2}}\\\\ =\mathsf{3\sqrt{2}}\\\\\\ \therefore~~\boxed{\begin{array}{c}\mathsf{(g\circ f)(-2)=3\sqrt{2}} \end{array}}\qquad\checkmark \end{array}](https://tex.z-dn.net/?f=%5Clarge%5Cbegin%7Barray%7D%7Bl%7D%20%5Ctextsf%7Bb%29%20%7D%5Cmathsf%7B%28g%5Ccirc%20f%29%28-2%29%7D%5C%5C%5C%5C%20%3D%5Cmathsf%7Bg%5Cbig%5Bf%28-2%29%5Cbig%5D%7D%5C%5C%5C%5C%20%3D%5Cmathsf%7B%5Csqrt%7Bf%28-2%29%7D%7D%5C%5C%5C%5C%20%3D%5Cmathsf%7B%5Csqrt%7B%28-2%29%5E2-6%5Ccdot%20%28-2%29%2B2%7D%7D%5C%5C%5C%5C%20%3D%5Cmathsf%7B%5Csqrt%7B4%2B12%2B2%7D%7D%5C%5C%5C%5C%20%3D%5Cmathsf%7B%5Csqrt%7B18%7D%7D%5C%5C%5C%5C%20%3D%5Cmathsf%7B%5Csqrt%7B3%5E2%5Ccdot%202%7D%7D%5C%5C%5C%5C%20%3D%5Cmathsf%7B3%5Csqrt%7B2%7D%7D%5C%5C%5C%5C%5C%5C%20%5Ctherefore~~%5Cboxed%7B%5Cbegin%7Barray%7D%7Bc%7D%5Cmathsf%7B%28g%5Ccirc%20f%29%28-2%29%3D3%5Csqrt%7B2%7D%7D%20%5Cend%7Barray%7D%7D%5Cqquad%5Ccheckmark%20%5Cend%7Barray%7D)
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Tags: <em>composite function composition evaluate algebra</em>
Don't listen to the other guy. The ANSWER is A). 1209. Your welcome!
Measure B is 90 because 17x+=180/2
and x=5
when you plug that into 17x+5 you get 90
