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bagirrra123 [75]
3 years ago
6

What must be true in order for line A to be parallel of line b?

Mathematics
2 answers:
AysviL [449]3 years ago
5 0

Answer:

Its the first option.

Step-by-step explanation:

if they are both 180° then they can both go on forever without touching each other.

pogonyaev3 years ago
4 0

Answer:

c or (5x-54)°=(3x+16)°

Step-by-step explanation:

Since they are alternate angles, they must be equal. Alternate angles are always equivalent, and since you can't choose more than one answer, then they can't equal 180° or 90°.

You might be interested in
Determine if true:<br> 24+24-8x2=80
Savatey [412]
Answer:true

Explanation:
24+24=48
48-8=40
40x2=80
80=80!

So it is true.
5 0
2 years ago
50r − 6 = 82r − 70.<br> a. r=64<br> b. r= -64<br> c.r=2<br> d.r=-2
lisabon 2012 [21]

Answer:

c

Step-by-step explanation:

Hope this helps.

3 0
3 years ago
all missing assignments are due today and I head help!!!! how many solutions are in y=-4/9x-3 Y=-7/5x-3
fiasKO [112]

Answer

Where is the picture

Step-by-step explanation:

4 0
3 years ago
Please help i have no clue
kozerog [31]

Answer:

Step-by-step explanation:

Question (1)

x² + 10x + 12

= x² + 2(5x) + 5² - 5² + 12

= [x² + 2(5x) + 5²] - 5² + 12

= (x + 5)² - 25 + 12 [Since, a² + 2ab + b² = (a + b)²]

= (x + 5)² - 13

Question (2)

y² - 6y - 15

= y² - 2(3y) - 15

= y² - 2(3y) + 3² - 3² - 15

= [y² - 2(3y) + 3²] - 3² - 15 [Since, a² - 2ab + b² = (a - b)²]

= (y - 3)² - 3²- 15

= (y - 3)² - 9 - 15

= (y - 3)² - 24

6 0
3 years ago
Hello, I am currently very stuck with this problem and I am unsure as to how I would solve it.
borishaifa [10]

We have the equation

20y=x^2-10-15

Let's complete the square, to do it let's add and subtract 25 on the right side

\begin{gathered} 20y=x^2-10-15+25-25 \\  \\ 20y=(x-5)^2-15-25_{} \\  \\ 20y=(x-5)^2-40 \\  \\  \end{gathered}

Now we can have y in function of x

\begin{gathered} y=\frac{1}{20}(x-5)^2-2 \\  \\  \end{gathered}

Now we can already identify the vertex because it's in the vertex form:

y=a(x-h)+k

Where the vertex is

(h,k)

As we can see, h = 5 and k = -2, then the vertex is

(5,-2)

Now we can continue and find the focus, the focus is

\mleft(h,k+\frac{1}{4a}\mright)

We have a = 1/20, therefore

\begin{gathered} \mleft(5,-2+5\mright) \\  \\ (5,3) \end{gathered}

The focus is

(5,3)

And the last one, the directrix, it's

y=k-\frac{1}{4a}

Then

\begin{gathered} y=-2-5 \\  \\ y=-7 \end{gathered}

Hence the correct answer is: vertex (5, -2); focus (5, 3); directrix y = -7

5 0
1 year ago
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