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3 years ago

Select the best answer for the question. 10. Divide 715 by 5.

Mathematics

1 answer:

MAXImum [283]3 years ago

7 0

Answer:143

Step-by-step explanation:5 goes into 715 143 times

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The vertex of this parabola is at (2,-1) when the y value is 0 and then x value is 5 what is the coefficient of the squared term

Darina [25.2K]

$\bf ~~~~~~\textit{parabola vertex form} \\\\ \begin{array}{llll} \stackrel{\textit{we'll use this one}}{y=a(x- h)^2+ k}\\\\ x=a(y- k)^2+ h \end{array} \qquad\qquad vertex~~(\stackrel{2}{ h},\stackrel{-1}{ k}) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{cases} h=2\\ k=-1 \end{cases}\implies y=a(x-2)^2-1 \\\\\\ \textit{we also know that } \begin{cases} y=0\\ x=5 \end{cases}\implies 0=a(5-2)^2-1\implies 1=9a \\\\\\ \cfrac{1}{9}=a\qquad therefore\qquad \boxed{y=\cfrac{1}{9}(x-2)^2-1}$

now, let's expand the squared term to get the standard form of the quadratic.

$\bf y=\cfrac{1}{9}(x-2)^2-1\implies y=\cfrac{1}{9}(x^2-4x+4)-1 \\\\\\ y=\cfrac{1}{9}x^2-\cfrac{4}{9}x+\cfrac{4}{9}-1\implies \stackrel{its~coefficient}{y=\stackrel{\downarrow }{\cfrac{1}{9}}x^2-\cfrac{4}{9}x-\cfrac{5}{9}}$

4 0

2 years ago

Read 2 more answers

What is the interquartile range of the box and whisker plot

Irina18 [472]

Answer:

(IQR) interquartile range = 5

Step-by-step explanation:

Lower quartile: 48

Upper quartile: 53

Median: 52

Lowest value: 46

Highest value: 55

(IQR) interquartile range: Upper quartile - Lower quartile = final answer

(IQR) interquartile range: 53 - 48 = 5

5 0

3 years ago

Two professional baseball teams played a four game series. Attendance for the first three games was 126,503 people, what was the

ioda

Answer: 44,815 people; 126,503 + n = 171,318; n = 171,318 − 126,503

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2 years ago

In a study investigating a link between walking and improved health, researchers reported that adults walked an average of 873

Rainbow [258]

Answer:

$H_0:\mu =873\\\\H_a: \mu$

Step-by-step explanation:

Given : In a study investigating a link between walking and improved health, researchers reported that adults walked an average of 873 minutes in the past month for the purpose of health or recreation.

Claim : The true average number of minutes in the past month that adults walked for the purpose of health or recreation is lower than 873 minutes.

i.e. $\mu$

We know that the null hypothesis contains equal sign , then the set of hypothesis for the given situation will be :-

$H_0:\mu =873\\\\H_a: \mu$

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2 years ago

X+y-6=0, x-y=0. What is the solution set of the system?<br><br>A. (3,3)<br>B. (-3,3)<br>C. (3, -3)

Vedmedyk [2.9K]

Answer:

A. (3,3)

Step-by-step explanation:

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2 years ago