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LenaWriter [7]
2 years ago
11

Can someone just tell me which ones are correct and which ones are wrong?

Mathematics
1 answer:
lozanna [386]2 years ago
6 0
First row all correct second rows all wrong and the first on of third row is correct be the last two are incorrect
You might be interested in
Please help. Thank you. :)
adelina 88 [10]
Hello!

To find the lateral area you use the equation

\pi r \sqrt{ h^{2} + r^{2} }

You put in the values you know and you get 829.4

To find the surface area you use the equation

\pi r(r+ \sqrt{ h^{2} + r^{2} }

Put in the values you know and you get 1209.5

The answer is A

Hope this helps!
5 0
2 years ago
Ed is doing a survey of popular colors for cars for a school report. He decides to take a sample by sitting near a busy intersec
o-na [289]
Answer: There are 12 white and blue cars more than silver and red cars

Number of white cars: n1=25
Number of blue cars: n2=17
Number of white and blue cars: n3=n1+n2=25+17→n3=42

Number of silver cars: n4=21
Number of red cars: n5=9
Number of silver and red cars: n6=n4+n5=21+9→n6=30

How many more white and blue cars are there than silver and red cars?
n=?

n=n3-n6=42-30→n=12

Answer: There are 12 white and blue cars more than silver and red cars.
4 0
2 years ago
Read 2 more answers
The number of pedestrian fatalities in the United States declined approximately steadily from 4,795 fatalities in 2006 to 4165 f
murzikaleks [220]

Answer:

Average rate of change = 0.1313 or 13.13% (approx.)

Step-by-step explanation:

Given:

Pedestrian fatalities in 2006 = 4,795

Pedestrian fatalities in 2009 = 4,165

Find:

Average rate of change

Computation:

Average rate of change = [4,165-4,795] / 4,795

Average rate of change = [-630] / 4,795

Average rate of change = 0.1313 or 13.13% (approx.)

3 0
2 years ago
Need help 10. solve inequality.<img src="https://tex.z-dn.net/?f=12c%20%5Cleq%2072" id="TexFormula1" title="12c \leq 72" alt="12
Sphinxa [80]
Hey, here’s your answer :)

4 0
2 years ago
The Westbrook Pharmaceutical Company manufactures atorvastatin pills, designed to lower cholesterol levels. Listed below are the
Sloan [31]

Solution :

Given :

$\mu = 24$

n = 15

$\overline x = 24.89$

s = 0.5902

The hypothesis :

$H_0 : \mu = 25$

$H_a : \mu \neq 25$

This is a 2 tailed test.

The significance level is $95 \% \ ( \alpha =0.05)$

The test statistic :

$Z=\frac{\overline x - \mu}{\frac{\sigma}{\sqrt n}}$

$Z=\frac{24.89-25}{\frac{0.5902}{\sqrt 15}}$

   = -0.72

The p value : The p value for Z = -0.72 is 0.4716

The critical value : the critical value at α = 0.05 is +1.96 to -1.96

The decision rule :

If $Z_{observed} > Z_{critical}$ or if $Z_{observed} < -Z_{critical}$, then reject $H_0$.

Also if p value is less than α, then reject $H_0$.

The decision :

Since the Z falls in between +1.96 and -1.96, we fail to reject the $H_0$. Also since p value is greater than α, we fail to reject  $H_0$.

The conclusion :

There is not sufficient evidence at the 95% significance level to warrant rejection of the claim that the pills come from a population in which the amount of the atorvastatin is equal to 25 mg.

Now calculating the mean and the standard deviation :

$\text{Mean} = \frac{\text{sum of observation}}{\text{total observations}}$

Standard deviation = $\sqrt{\text{variance}}$

Variance = $\frac{\text{sum of squares(SS)}}{n-1}$

Where, SS = $\sum (X - \text{mean})^2$

X                   Mean                 $(X-\text{mean})^2$

24.1               24.89                    0.62

24.4              24.89                     0.24

24.3              24.89                    0.35

24.9             24.89                       0

24.1              24.89                    0.62

24.2             24.89                    1.72

24.1              24.89                    0.04

26.2             24.89                    0.04

25.1              24.89                   0.24

25                24.89                    0.01

24.7             24.89                    0.04

25.1             24.89                    0.04

25.3             24.89                   0.17

25.5             24.89                   0.37

25.5            24.89                   0.37

n                                                   15

Sum                                           373.3

Average                                    24.89

SS                                              4.8775

Variance = $\frac{SS}{n-1}$                       0.348392857

Standard deviation                    0.5902      

3 0
2 years ago
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