Answer:
Step-by-step explanation:
Frequency table for the height of the seedlings,
Height (in inches) Number of seedlings
2
4
2
2
Now we can draw the line plot as attached.
Average height of the seedlings = 
= 
= 
Answer:
just do cross multiplication
Step-by-step explanation:
then ans will come
Answer:
5/3 or 10/12
Step-by-step explanation:
Answer:
Step-by-step explanation:
<em>Given that X - the distribution of heights of male pilots is approximately normal, with a mean of 72.6 inches and a standard deviation of 2.7 inches.</em>
<em />
<em>Height of male pilot = 74.2 inches</em>
<em />
<em>We have to find the percentile</em>
<em />
<em>X = 74.2</em>
<em />
<em>Corresponding Z score = 74.2-72.6 = 1.6</em>
<em />
<em>P(X<174.2) = P(Z<1.6) = 0.5-0.4452=0.0548=5.48%</em>
<em />
<em>i.e. only 5% are below him in height.</em>
<em />
<em>Thus the malepilot is in 5th percentile.</em>
Answer:
Step-by-step explanation:
