<img src="https://tex.z-dn.net/?f=2x%5E2-20x%3Dx%5E%7B2%7D%20-19" id="TexFormula1" title="2x^2-20x=x^{2} -19" alt="2x^2-20x=x^{2

Kaylis [27]

3 years ago

} -19" align="absmiddle" class="latex-formula">

Mathematics

2 answers:

ASHA 777 [7]3 years ago

8 0

x1 = 1 x2 = 19 if I’m correct

WINSTONCH [101]3 years ago

4 0

Answer:

x = 1, x = 19

Step-by-step explanation:

Given

2x² - 20x = x² - 19 ( subtract x² - 19 from both sides )

x² - 20x + 19 = 0 ← in standard form

(x - 1)(x - 19) = 0 ← in factored form

Equate each factor to zero and solve for x

x - 1 = 0 ⇒ x = 1

x - 19 = 0 ⇒ x = 19

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