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musickatia [10]
3 years ago
7

Can someone please help me with this questions

Mathematics
1 answer:
Ludmilka [50]3 years ago
8 0

Step-by-step explanation:

a. 3⁴

b. 7⁵

c. 10²

d. 5⁷

Hope this helps?

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Which of the following tables represents a function?
Y_Kistochka [10]

Answer:

The second one:

x 2-2 3-3

y 5 5 7 7

Step-by-step explanation:

Each domain value or x can only have one range, y, so, with that said, the second one is the answer.

5 0
2 years ago
How many arrangements of three letter can be formed from the letters of the word MATH if anyletter will not be used more than on
Mariulka [41]

Combinations = n! / (n - r)! r!

C\text{ = }\frac{n!}{(n-r)!\text{ r!}}\text{ }

In this case:

n = 4

r = 3

Combinations = 4! /(4-3)! 3! = 24/(1)(6) = 24/6 = 4

Answer:

4 arrangements

7 0
1 year ago
Not sure what to do here can someone please help
kumpel [21]

Answer:

  x = 2

Step-by-step explanation:

These equations are solved easily using a graphing calculator. The attachment shows the one solution is x=2.

__

<h3>Squaring</h3>

The usual way to solve these algebraically is to isolate radicals and square the equation until the radicals go away. Then solve the resulting polynomial. Here, that results in a quadratic with two solutions. One of those is extraneous, as is often the case when this solution method is used.

  \sqrt{x+2}+1=\sqrt{3x+3}\qquad\text{given}\\\\(x+2)+2\sqrt{x+2}+1=3x+3\qquad\text{square both sides}\\\\2\sqrt{x+2}=(3x+3)-(x+3)=2x\qquad\text{isolate the root term}\\\\x+2=x^2\qquad\text{divide by 2, square both sides}\\\\x^2-x-2=0\qquad\text{write in standard form}\\\\(x-2)(x+1)=0\qquad\text{factor}

The solutions to this equation are the values of x that make the factors zero: x=2 and x=-1. When we check these in the original equation, we find that x=-1 does not work. It is an extraneous solution.

  x = -1: √(-1+2) +1 = √(3(-1)+3)   ⇒   1+1 = 0 . . . . not true

  x = 2: √(2+2) +1 = √(3(2) +3)   ⇒   2 +1 = 3 . . . . true . . . x = 2 is the solution

__

<h3>Substitution</h3>

Another way to solve this is using substitution for one of the radicals. We choose ...

  u=\sqrt{x+2}\qquad\text{requires $u\ge0$}\\\\u^2-2=x\qquad\text{solve for x}\\\\u+1=\sqrt{3(u^2-2)+3}\qquad\text{substitute for x in the original equation}\\\\(u+1)^2=3u^2-3\qquad\text{square both sides, simplify a little}\\\\2u^2-2u-4=0\qquad\text{subtract $(u+1)^2$}\\\\2(u-2)(u+1)=0\qquad\text{factor}

Solutions to this equation are ...

  u = 2, u = -1 . . . . . . the above restriction on u mean u=-1 is not a solution

The value of x is ...

  x = u² -2 = 2² -2

  x = 2 . . . . the solution to the equation

_____

<em>Additional comment</em>

Using substitution may be a little more work, as you have to solve for x in terms of the substituted variable. It still requires two squarings: one to find the value of x in terms of u, and another to eliminate the remaining radical. The advantage seems to be that the extraneous solution is made more obvious by the restriction on the value of u.

6 0
2 years ago
WILL GIVE BRAINLIEST AND 13 POINTS!!!!!! When you measure the length of an object to the eighth of an inch and again to the four
Savatey [412]

The smaller the value of the least increment, the more precise a number is.

Length measured to the nearest 1/8 inch will be more precisely specified than length measured to the nearest 1/4 inch.

_____

In general, precision has little to do with accuracy—how close the measured value is to the actual value. A measurement can be very precise, but just plain wrong. (Many electronic instruments have resolution (precision) that exceeds their accuracy. That is, one or two (or more) of the least-significant displayed digits may be in error.)

7 0
3 years ago
Read 2 more answers
A sample of n = 4 scores has SS = 48. What is the estimated standard error for this sample? Group of answer choices
mylen [45]

Answer:

2

Step-by-step explanation:

We have

n = 4 scores

SS = 48

For this question, we are required to find the estimated standard error

To get this, we first solve for the variance

S² = SS/n-1

= 48/4-1

= 48/3

= 16

Then S² = 16

S = √16

S = 4

Then the estimated standard error is given by:

S/√n

= 4/√4

= 4/2

= 2.

The estimated standard error is 2.

4 0
2 years ago
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