Answer:
The second one:
x 2-2 3-3
y 5 5 7 7
Step-by-step explanation:
Each domain value or x can only have one range, y, so, with that said, the second one is the answer.
Combinations = n! / (n - r)! r!

In this case:
n = 4
r = 3
Combinations = 4! /(4-3)! 3! = 24/(1)(6) = 24/6 = 4
Answer:
4 arrangements
Answer:
x = 2
Step-by-step explanation:
These equations are solved easily using a graphing calculator. The attachment shows the one solution is x=2.
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<h3>Squaring</h3>
The usual way to solve these algebraically is to isolate radicals and square the equation until the radicals go away. Then solve the resulting polynomial. Here, that results in a quadratic with two solutions. One of those is extraneous, as is often the case when this solution method is used.

The solutions to this equation are the values of x that make the factors zero: x=2 and x=-1. When we check these in the original equation, we find that x=-1 does not work. It is an extraneous solution.
x = -1: √(-1+2) +1 = √(3(-1)+3) ⇒ 1+1 = 0 . . . . not true
x = 2: √(2+2) +1 = √(3(2) +3) ⇒ 2 +1 = 3 . . . . true . . . x = 2 is the solution
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<h3>Substitution</h3>
Another way to solve this is using substitution for one of the radicals. We choose ...

Solutions to this equation are ...
u = 2, u = -1 . . . . . . the above restriction on u mean u=-1 is not a solution
The value of x is ...
x = u² -2 = 2² -2
x = 2 . . . . the solution to the equation
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<em>Additional comment</em>
Using substitution may be a little more work, as you have to solve for x in terms of the substituted variable. It still requires two squarings: one to find the value of x in terms of u, and another to eliminate the remaining radical. The advantage seems to be that the extraneous solution is made more obvious by the restriction on the value of u.
The smaller the value of the least increment, the more precise a number is.
Length measured to the nearest 1/8 inch will be more precisely specified than length measured to the nearest 1/4 inch.
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In general, precision has little to do with accuracy—how close the measured value is to the actual value. A measurement can be very precise, but just plain wrong. (Many electronic instruments have resolution (precision) that exceeds their accuracy. That is, one or two (or more) of the least-significant displayed digits may be in error.)
Answer:
2
Step-by-step explanation:
We have
n = 4 scores
SS = 48
For this question, we are required to find the estimated standard error
To get this, we first solve for the variance
S² = SS/n-1
= 48/4-1
= 48/3
= 16
Then S² = 16
S = √16
S = 4
Then the estimated standard error is given by:
S/√n
= 4/√4
= 4/2
= 2.
The estimated standard error is 2.