Find the product of this square of a binomial. (2x

QUESTION :-

Galina-37 [17]

Answer:

92000

Step-by-step explanation:

Given:

I = 5% = 0.05
t = 2 years
Let the sum is x.

Simple interest:

SI = x*2*0.05 = 0.1x

Compound interest:

CI = x*(1 + 0.05)² - x = 1.1025x - x = 0.1025x

The difference is 230:

0.1025x - 0.1x = 230
0.0025x = 230
x = 230/0.0025
x = 92000

3 0

2 years ago

Kay's Dessert Shop bakes cookies. The ratio of chocolate chip to sugar cookies baked is always 5 to 2. If she bakes 210 cookies

Gnom [1K]

Answer: 60

Step-by-step explanation:

Given

The ratio of chocolate chip to sugar cookies is 5:2

If she bakes 210 cookies in one day

Suppose she baked x amount of chocolate chips on that day

So, we can write

$\Rightarrow x=\dfrac{2}{5+2}\times 210\\\\\Rightarrow x=\dfrac{2}{7}\times 210=60$

There were 60 sugar cookies on that day

6 0

2 years ago

How many solutions does the system of equations have?

Vlad1618 [11]

Answer:

one solution at x=1,y=4 point

4 0

2 years ago

Read 2 more answers

Discuss two other ways in which you encounter percentages in a typical week of your life

djverab [1.8K]

1) In school, you will encounter percentages on class assignments to see how much progress you made in an subject. 2) On a cell phone, you encounter percentages by how much your cell phone is charged in order to know if you need to charge the battery or not.

8 0

2 years ago

The distribution of weekly salaries at a large company is right skewed with a mean of $1000 and a standard deviation of $350. Wh

Shtirlitz [24]

Answer:

68.76% probability that the sampling error made in estimating the mean weekly salary for all employees of the company by the mean of a random sample of weekly salaries of 50 employees will be at most $50

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation, which is also called standard error $s = \frac{\sigma}{\sqrt{n}}$

In this problem, we have that:

$\mu = 1000, \sigma = 350, n = 50, s = \frac{350}{\sqrt{50}} = 49.5$

What is the probability that the sampling error made in estimating the mean weekly salary for all employees of the company by the mean of a random sample of weekly salaries of 50 employees will be at most $50

This is the pvalue of Z when X = 1000+50 = 1050 subtracted by the pvalue of Z when X = 1000-50 = 950. So

X = 1050

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{1050-1000}{49.5}$

$Z = 1.01$

$Z = 1.01$ has a pvalue of 0.8438

X = 950

$Z = \frac{X - \mu}{s}$

$Z = \frac{950-1000}{49.5}$

$Z = -1.01$

$Z = -1.01$ has a pvalue of 0.1562

0.8438 - 0.1562 = 0.6876

68.76% probability that the sampling error made in estimating the mean weekly salary for all employees of the company by the mean of a random sample of weekly salaries of 50 employees will be at most $50

4 0

2 years ago

Find the product of this square of a binomial. (2x - 3)^2