Graph the linear function whose equation is y - 2 = - (x + 1)
1 answer:
Answer:
<h2>In the attachment</h2>Step-by-step explanation:
Convert to the slope-intercept form (<em>y = mx + b</em>):
y - 2 = -(x + 1) <em>use the distributive property</em>
y - 2 = -x - 1 <em>add 2 to both sides</em>
y - 2 + 2 = -x - 1 + 2
y = -x + 1
We only need two points to plot the graph of the linear function.
Select any two x values. Insert them into the equation.
Calculate the value of y.
For x = 1:
y = -1 + 1 = 0 → (1, 0)
For x = 0:
y = -0 + 1 = 1 → (0, 1)
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Answer:
1. reflection across x-axis
2. translation 6 units to the right and 3 units up (x+6,y+3)
Step-by-step explanation:
The trapezoid ABCD has it vertices at points A(-5,2), B(-3,4), C(-2,4) and D(-1,2).
First transformation is the reflection across the x-axis with the rule
(x,y)→(x,-y)
so,
- A(-5,2)→A'(-5,-2)
- B(-3,4)→B'(-3,-4)
- C(-2,4)→C'(-2,-4)
- D(-1,2)→D'(-1,-2)
Second transformation is translation 6 units to the right and 3 units up with the rule
(x,y)→(x+6,y+3)
so,
- A'(-5,-2)→E(1,1)
- B'(-3,-4)→H(3,-1)
- C'(-2,-4)→G(4,-1)
- D'(-1,-2)→F(5,1)
