Given:
The side lengths of two cubes are 12 ft and 6 ft.
To find:
The side length of third cube.
Solution:
From the given figure it is clear that the cubes are inclined to each other in such a way so that they form a right angle triangle and side length of third cube is the hypotenuse.
Let x be the side length of the third cube.
Using Pythagoras theorem, we get
Taking square root on both sides, we get
Side cannot be negative. So,
Therefore, the side length of the third cube is ft.
Answer:
A. x = 1/2at²
Step-by-step explanation:
Among the equations, the equation that is dimensionally consistent is x=1/2at² where;
x is the distance in meters (dimension is length (L))
a is the acceleration in m/s² (dimension is L/T²)
t is the time in seconds (s) (dimension of time is T)
Substituting the dimensions into the formula to check if we are going to arrive at the dimension for distance;
1/2at² = 1/2(L/T²)T²
= 1/2× L/T² × T²
= 1/2 × L
Since L which is the resulting dimension is the dimension for distance (x), this means that the equation x = 1/2at² is dimensionally consistent.
Each student got 1/4 because thats half of 1/2
The value of –3mn + 4 = –3 when m = 2 and n = 4 is –20
Solution:
Given expression is –3mn + 4 = –3.
To find the value of –3mn + 4 = –3 when m = 2 and n = 4.
⇒ –3mn + 4 = –3
Add 3 on both sides of the equation.
⇒ –3mn + 4 + 3 = –3 + 3
⇒ –3mn + 7 = 0
Substitute m = 2 and n = 4
⇒ –3 × 2 × 4 + 7
Using BODMAS rule first do the multiplication.
⇒ –6 × 4 + 4
⇒ –24 + 4
⇒ –20
Hence the value of –3mn + 4 = –3 when m = 2 and n = 4 is –20.
Answer:
You're a gift from god, an absolute chad. Godspeed chadman.
Step-by-step explanation:
