Answer:
10, 12, 14, 16
Step-by-step explanation:
Given: Four consecutive even integers such that seven times the first exceeds their sum by 18.
Lets assume the first number be "x".
As it is even integers
∴ Second consecutive number will be 
Third consecutive number will be 
Fourth consecutive number will be 
Now, as given seven times the first exceeds their sum by 18.
∴ ![[x+(x+2)+(x+4)+(x+6)]+18 = 7x](https://tex.z-dn.net/?f=%5Bx%2B%28x%2B2%29%2B%28x%2B4%29%2B%28x%2B6%29%5D%2B18%20%3D%207x)
solving the equation to find the number.
⇒ ![[x+(x+2)+(x+4)+(x+6)]+18 = 7x](https://tex.z-dn.net/?f=%5Bx%2B%28x%2B2%29%2B%28x%2B4%29%2B%28x%2B6%29%5D%2B18%20%3D%207x)
Opening parenthesis

⇒ 
subtracting both side by 4x
⇒ 
Dividing both side by 3
∴ x= 10.
Hence, subtituting the value x to find four consecutive even integers.
First number is 10
Second consecutive number will be
= 12
Third consecutive number will be
= 14
Fourth consecutive number will be
= 16
∴ Four consecutive even integers are 10,12,14,16.