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IceJOKER [234]
3 years ago
10

Select three ratios that are equivalent to 4:18

Mathematics
1 answer:
Alex777 [14]3 years ago
4 0

Answer:

8:36 16:72 and 2:9

Step-by-step explanation:

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Please help me really quick pleasee<br> answer choices:<br> a)2<br> b)11<br> c)20<br> d)29
mihalych1998 [28]

Answer:

C. x=20^{\circ}

Step-by-step explanation:

Angle 6 and angle with measure 45° are vertical angles (opposite angles whan two lines intersect). By Vertical Angles Theorem, vertical angles are congruent, so

m\angle 6=45^{\circ}

Angle 6 and angle with measure 5x+35^{\circ} are the same side interior angles when two parallel lines are cut by transversal. The same side interior angles add up to 180°, then

m\angle 6+5x+35^{\circ}=180^{\circ}\\ \\45^{\circ}+5x+35^{\circ}=180^{\circ}\\ \\5x=180^{\circ}-45^{\circ}-35^{\circ}\\ \\5x=100^{\circ}\\ \\x=20^{\circ}  

7 0
3 years ago
Find the value of a and b if root3-1/root3+1+ root3+1/root3-1=a+root3 b​
Digiron [165]

Answer:

a=4 and b = 0

Step-by-step explanation:

Given : \dfrac{\sqrt 3 -1}{\sqrt 3+1}+\dfrac{\sqrt 3+1}{\sqrt 3-1}=a+\sqrt 3 b

To find, The value of a and b

Solution,

Solving LHS of the given equation,

\dfrac{(\sqrt 3-1)^2+(\sqrt3+1)^2}{(\sqrt 3+1)(\sqrt 3-1)}=a+\sqrt 3 b

Since,

(a-b)^2=a^2+b^2-2ab\\\\(a+b)^2=a^2+b^2+2ab\\\\(a-b)(a+b)=a^2+b^2

So,

\dfrac{3+1-2\sqrt 3+3+1+2\sqrt 3}{3-1}=a+\sqrt 3 b\\\\4=a+\sqrt 3 b

or

4+0=a+\sqrt 3 b

On comparing we get :

a = 4 and b = 0

4 0
3 years ago
Solve ax + bx = c for x <br> a,b,c represent nonzero constants
Zepler [3.9K]

Answer:

x=(c/a+b)

Step-by-step explanation:

..........

4 0
3 years ago
Read 2 more answers
Test the claim that the mean GPA of Orange Coast students is smaller than the mean GPA of Coastline students at the 0.005 signif
algol [13]

Answer:

a) F. H 0 : μ O ≥ μ C

H 1 : μ O < μ C

b) B. two-tailed

d) t=\frac{(2.91-2.96)-0}{\sqrt{\frac{0.05^2}{60}+\frac{0.03^2}{60}}}}=-6.64  

e) p_v =P(t_{118}  

f) B. Reject the null hypothesis

Step-by-step explanation:

Information provided

\bar X_{O}=2.91 represent the mean for the Orange Coast

\bar X_{C}=2.96 represent the mean for the Coastline

s_{O}=0.05 represent the sample standard deviation for Orange Coast

s_{C}=0.03 represent the sample standard deviation for Coastline

n_{O}=60 sample size for Orange Coast

n_{C}=60 sample size for Coastline

\alpha=0.005 Significance level provided

t would represent the statistic

Part a

For this case we want to test the claim that the mean GPA of Orange Coast students is smaller than the mean GPA of Coastline students

Null hypothesis:\mu_{O} \geq \mu_{C}  

Alternative hypothesis:\mu_{O} < \mu_{C}  

F. H 0 : μ O ≥ μ C

H 1 : μ O < μ C

Part b

For this case we need to conduct a left tailed test.

B. two-tailed

Part d

The statistic is given by:

t=\frac{(\bar X_{O}-\bar X_{C})-\Delta}{\sqrt{\frac{s^2_{O}}{n_{O}}+\frac{s^2_{C}}{n_{C}}}} (1)  

And the degrees of freedom are given by df=n_1 +n_2 -2=60+60-2=118  

Replacing the info we got:

t=\frac{(2.91-2.96)-0}{\sqrt{\frac{0.05^2}{60}+\frac{0.03^2}{60}}}}=-6.64  

Part e

We can calculate the p value with this probability:

p_v =P(t_{118}  

Part f

Since the p value is a very low value compared to the significance level given of 0.005 we can reject the null hypothesis.

B. Reject the null hypothesis

5 0
3 years ago
A square has side length of 5 cm. The square was changed using a scale factor of 0.6.
Aliun [14]
So the side length became 0.6*5  = 3 cm.
8 0
3 years ago
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