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ElenaW [278]
3 years ago
13

I WILL GIVE BRAINLEST FOR THE CORRECT ANSWER!

Mathematics
1 answer:
pentagon [3]3 years ago
3 0

Answer:

A) -4

B) 4 units apart

C) no values of x

Step-by-step explanation:

1) slope of m: (3-2)/(10-8) = ½

m(x) = ½x + c

2 = ½(8) + c

c = -2

m(x) = ½x - 2

m(16) = 6

h(4) = (4-2)²/2 = 4/2 = 2

h(4)-m(16) = 2-6 = -4

B) y-intercept of:

*h(x) = ½(0-2)² = 2

*m(x) = -2

from the equation found before

2 - (-2) = 4 units apart

C) m(x) = (x-4)/2

m(x) > h(x)

(x-4)/2 > ½(x-2)²

x-4 > x²-4x+4

x²-5x+8 < 0

(x - 2.5)² + 1.75 < 0

Never negative

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The graphs of the quadratic functions f(x) = 6 – 10x2 and g(x) = 8 – (x – 2)2 are provided below. Observe there are TWO lines si
natta225 [31]

Answer:

a) y = 7.74*x + 7.5

b)  y = 1.148*x + 6.036

Step-by-step explanation:

Given:

                                  f(x) = 6 - 10*x^2

                                  g(x) = 8 - (x-2)^2

Find:

(a) The line simultaneously tangent to both graphs having the LARGEST slope has equation

(b) The other line simultaneously tangent to both graphs has equation,

Solution:

- Find the derivatives of the two functions given:

                                f'(x) = -20*x

                                g'(x) = -2*(x-2)

- Since, the derivative of both function depends on the x coordinate. We will choose a point x_o which is common for both the functions f(x) and g(x). Point: ( x_o , g(x_o)) Hence,

                                g'(x_o) = -2*(x_o -2)

- Now compute the gradient of a line tangent to both graphs at point (x_o , g(x_o) ) on g(x) graph and point ( x , f(x) ) on function f(x):

                                m = (g(x_o) - f(x)) / (x_o - x)

                                m = (8 - (x_o-2)^2 - 6 + 10*x^2) / (x_o - x)

                                m = (8 - (x_o^2 - 4*x_o + 4) - 6 + 10*x^2)/(x_o - x)

                                m = ( 8 - x_o^2 + 4*x_o -4 -6 +10*x^2) /(x_o - x)

                                m = ( -2 - x_o^2 + 4*x_o + 10*x^2) /(x_o - x)

- Now the gradient of the line computed from a point on each graph m must be equal to the derivatives computed earlier for each function:

                                m = f'(x) = g'(x_o)

- We will develop the first expression:

                                m = f'(x)

                                ( -2 - x_o^2 + 4*x_o + 10*x^2) /(x_o - x) = -20*x

Eq 1.                          (-2 - x_o^2 + 4*x_o + 10*x^2) = -20*x*x_o + 20*x^2

And,

                              m = g'(x_o)

                              ( -2 - x_o^2 + 4*x_o + 10*x^2) /(x_o - x) = -20*x

                              -2 - x_o^2 + 4*x_o + 10*x^2 = -2(x_o - 2)(x_o - x)

Eq 2                       -2 - x_o^2 + 4*x_o+ 10*x^2 = -2(x_o^2 - x_o*(x + 2) + 2*x)

- Now subtract the two equations (Eq 1 - Eq 2):

                              -20*x*x_o + 20*x^2 + 2*x_o^2 - 2*x_o*(x + 2) + 4*x = 0

                              -22*x*x_o + 20*x^2 + 2*x_o^2 - 4*x_o + 4*x = 0

- Form factors:       20*x^2 - 20*x*x_o - 2*x*x_o + 2*x_o^2 - 4*x_o + 4*x = 0

                              20*x*(x - x_o) - 2*x_o*(x - x_o) + 4*(x - x_o) = 0

                               (x - x_o)(20*x - 2*x_o + 4) = 0  

                               x = x_o   ,     x_o = 10x + 2    

- For x_o = 10x + 2  ,

                               (g(10*x + 2) - f(x))/(10*x + 2 - x) = -20*x

                                (8 - 100*x^2 - 6 + 10*x^2)/(9*x + 2) = -20*x

                                (-90*x^2 + 2) = -180*x^2 - 40*x

                                90*x^2 + 40*x + 2 = 0  

- Solve the quadratic equation above:

                                 x = -0.0574, -0.387      

- Largest slope is at x = -0.387 where equation of line is:

                                  y - 4.502 = -20*(-0.387)*(x + 0.387)

                                  y = 7.74*x + 7.5          

- Other tangent line:

                                  y - 5.97 = 1.148*(x + 0.0574)

                                  y = 1.148*x + 6.036

6 0
3 years ago
7. What is the image of p for a dilation with center (0,0) and a scale factor of 2.5?
natta225 [31]

Answer:

A (-2.5, 5) Might Not Be Right

Step-by-step explanation:

3 0
3 years ago
An aircraft manufacturer wants to determine the best selling price for a new airplane. The company estimates that the initial co
Ad libitum [116K]

Answer:

The cost function is simply the initial cost plus the manufacturing cost.

C(x)=500+20x-5x^3/4+0.01x^2

The demand function was given to us.

p(x)=320-7,7x

The revenue function is simply x multiplied by the demand function.

R(x)=xp(x)=320x-7.7x^2

We find that when 20 planes are produced, that profit is currently maximized

We know that to maximize profit, marginal revenue must equal marginal cost.

C'(x)=20-15/4x^-1/4+0.02x

R'(x)=320-15.4x

x=19,57

We find that when 20 planes are produced, that profit is currently maximized.

Step-by-step explanation:

An aircraft manufacturer wants to determine the best selling price for a new airplane. The company estimates that the initial cost of designing the airplane and setting up the factories in which to build it will be 500 million dollars. The additional cost of manufacturing each plane can be modeled by the function: , where x is the number of aircraft produced and m is the manufacturing cost, in millions of dollars. The company estimates that if it charges a price p (in millions of dollars) for each plane, it will be able to sell  planes.

(a) Find the cost, demand, and revenue functions.

(b) Find th eproduction level and the associated selling price of the aircraft that maximizes profit.

3 0
3 years ago
ducational Television In a random sample of people, said that they watched educational television. Find the confidence interval
SIZIF [17.4K]

Complete Question

Educational Television In a random sample of 200 people, 159 said that they watched educational television. Find the 90% confidence interval of the true proportion of people who watched educational television. Round the answers to at least three decimal places.

Answer:

The 90% confidence interval is   0.748  <  p <  0.842      

Step-by-step explanation:

From the question we are told that

     The sample size is  n = 200

     The number of people that watched the educational television is k =  159

Generally the sample proportion is mathematically represented as

               \^ p =  \frac{159}{200}

=>               \^ p =  0.795

From the question we are told the confidence level is  90% , hence the level of significance is    

      \alpha = (100 - 90) \%

=>   \alpha = 0.10

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   Z_{\frac{\alpha }{2} } =  1.645

Generally the margin of error is mathematically represented as  

     E =  Z_{\frac{\alpha }{2} } * \sqrt{\frac{\^ p (1- \^ p)}{n} }

=>     E =  1.645  * \sqrt{\frac{0.795 (1- 0.795)}{200} }

=>     E = 0.04696

Generally 95% confidence interval is mathematically represented as  

      \^ p -E <  p <  \^ p +E

=>    0.795  -0.04696  <  p <  0.795 + 0.04696

=>    0.748  <  p <  0.842      

3 0
3 years ago
A pyramid shaped building is 311 feet tall and has a square base with sides of 619 ft. The sides of the building are made from r
zmey [24]

Answer:

Surface area of the reflective glass is 543234.4 square feet.

Step-by-step explanation:

Given that: height = 311 feet, sides of square base = 619 feet.

To determine the slant height, we have;

l^{2} = 311^{2} + 309.5^{2}

   = 96721 + 95790.25

   = 192511.25

⇒ l = \sqrt{192511.25}

      = 438.761

The slant height, l is 438.8 feet.

Considering one reflecting surface of the pyramid, its area = \frac{1}{2} × base × height

  area =  \frac{1}{2} × 619 × 438.8

          = 135808.6

          = 135808.6 square feet

Since the pyramid has four reflective surfaces,

surface area of the reflective glass = 4 × 135808.6

                                                          = 543234.4 square feet

4 0
3 years ago
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