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andrey2020 [161]
4 years ago
7

Question: Michelle is making goodie bags for Christmas filled with chocolate and candy. Chocolates cost $2.50 per lb and candy c

ost $3.00 per lb. Michelle spent a total of $40 on 20 lbs of candy. How much of each kind of candy did she purchase ?
Mathematics
1 answer:
ehidna [41]4 years ago
4 0
The answer will be 80
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Change the mixed expressions to fractions y+2 y^3/x^3-y^3
Hatshy [7]
The common denominator for each of these terms is x^3 so the new expression would be:
\frac{x^{3}y}{x^{3}} +  \frac{y^{3}}{x^{3}} -  \frac{x^{3}y^{3}}{x^{3}}
so to simplify that down to a single fraction
\frac{x^3y + y^{3}-x^{3}y^{3}}{x^{3}}
6 0
3 years ago
At the Two Below store, every item is $2 less than the suggested retail price. If y is Two Below’s price, and x is the suggested
Vikki [24]

Answer:

Its B, y = x - 2

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
A circle in the standard (x,y) coordinate plane has
Otrada [13]

Given:

Center of a circle is at point C(-1,2).

AB is the diameter of the circle.

Coordinates of the point A are A(2,6).

To find:

The coordinates of point B.

Solution:

Let the coordinates of point B are (a,b).

If AB is the diameter of the circle, then A and B are end points of diameter of the circle and the center C is the midpoint of AB.

Midpoint=\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)

Point C = Midpoint of AB

(-1,2)=\left(\dfrac{2+a}{2},\dfrac{6+b}{2}\right)

On comparing both sides, we get

\dfrac{2+a}{2}=-1

2+a=-1\times 2

a=-2-2

a=-4

Similarly,

\dfrac{6+b}{2}=2

6+b=2\times 2

b=4-6

b=-2

Therefore, the coordinates of point B are (-4,-2).

8 0
3 years ago
Helppp please I’m desperate
IRINA_888 [86]
The elimination method works by adding the two equations and eliminating one variable. Then you solve an equation in one variable. Finally, you use substitution or elimination again to find the other variable. Sometimes, by simply adding the equations, a variable is not eliminated. Then you need to multiply one or both equations by a factor to get a variable to be eliminated.

A)
2x - 4y = 8
x + 3y = -11

Adding the equations does not eliminate x or y.
Notice that in the first equation, every coefficient is even. We can divide both sides of the first equation by 2. Then the first term would be x. Instead, let's divide both sides of the first equation by -2. Then the x's will be eliminated.

-x + 2y = -4   <-- The first equation divided by -2
x + 3y = -11  <-- The original second equation. Now we add the equations.
----------------
      5y = -15

        y = -3

Now that we know y = -3, we substitute it into the first original equation and solve for x.

2x - 4y = 8

2x - 4(-3) = 8

2x + 12 = 8

2x = -4

x = -2

Answer: x = -2; y = -3

B)
We see that the x's will be eliminated by addition. Just add the equations.

-3x + 7y = 9
 3x  - 7y = 1
---------------
   0 + 0   = 10

0 = 10  <---- this is a false statement, so this system of equations has no solution.
7 0
3 years ago
How do you do this?
lorasvet [3.4K]

Simplify so divide both sides by 4x. To get f= 0.24x^-1+0.5 Them simplify it to get   F=0.5+0.24x^-1

8 0
3 years ago
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