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user100 [1]
3 years ago
10

Find the annual interest rate.

Mathematics
1 answer:
slega [8]3 years ago
8 0

The annual interest rate is 3.5%.

Solution:

Given Interest (I) = $26.25

Principal (P) = $500

Time (t) = 18 months

Rate of interest (r) = ?

Time must be in years to find the rate per annum.

1 year = 12 months

Divide the time by 12.

Time (t) = \frac{18}{12}=\frac{3}{2} years

Now, find the rate of interest using simple interest formula.

<u>Simple interest formula:</u>

$I=\frac{Prt}{100}

$26.25=\frac{500\times r\times \frac{3}{2} }{100}

$26.25\times 100 =500\times r\times \frac{3}{2}

$2625 =250\times r\times 3

$2625 =750\times r

$\Rightarrow r=\frac{2625}{750}

⇒ r = 3.5%

Hence the annual interest rate is 3.5%.

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Answer:

a.\  \mu_p=750\ \ , \sigma_p=0.005\\\\b.\  \mu_p=150\ \ , \sigma_p=0.0113\\\\c.\  \mu_p=75\ \ , \sigma_p=0.0160

Step-by-step explanation:

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\mu_p=np\\\\=0.15\times 5000\\\\=750

-The standard deviation is calculated using the formula:

\sigma_p=\sqrt{\frac{p(1-p)}{n}}\\\\=\sqrt{\frac{0.15(1-0.15)}{5000}}\\\\=0.0050

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#The mean of a sampling proportion  of n=1000 is calculated as:

\mu_p=np\\\\=1000\times 0.15\\\\\\=150

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\sigma_p=\sqrt{\frac{p(1-p)}{n}}\\\\\\=\sqrt{\frac{0.15\times 0.85}{1000}}\\\\\\=0.0113

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\mu_p=np\\\\\\=0.15\times 500\\\\=75

#The standard deviation of the sample proportion is calculated as:

\sigma_p=\sqrt{\frac{p(1-p)}{n}}\\\\\\=\sqrt{\frac{0.15\times 0.85}{500}}\\\\\\=0.0160

Hence, the sample mean is μ=75 and standard deviation is σ=0.0160

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