The answer is 22 a means increase value of a immediately what is the value of a it is 10,no it will change it value by 1 if it use again so from above line it’s value is 11 and than increase value of a immediately its value is 12 so value of B=22
Answer:
The answer is "The product is greater than 3/8 and less than 7/2"
Step-by-step explanation:
This is because the product of 3/8 and 7/2 is 21/16.
When you simplify 21/16, you get 1 and 5/16 which is greater than 3/8 but less than 7/2, which simplified is 3 and 1/2.
Answer: y=x+5
Step-by-step explanation:
So the dots are going at a slope of 1 up and 1 right each time, so your slope would be 1, or simply x if you times it. To line it up with the slope, you have to move up 5 on your y-axis, known as your b. Then from there, you go up 1 over 1 which will line up with all the dots.
Answer:
<u>The standard error of distribution for n = 4 is 5 and for n = 25 is 2.</u>
Step-by-step explanation:
1. Let's review the information given to us for solving the question:
Population mean = 72
Standard deviation = 10
Sample₁ = 4
Sample₂ = 25
2. For finding the standard error of the mean, we use the following formula:
Standard error = Standard deviation / √Size of the sample
Standard error for Sample₁ = 10/√4
<u>Standard error for Sample₁ = 10/2 = 5</u>
Now, let's find the standard error for Sample₂
Standard error for Sample₂ = 10/√25
<u>Standard error for Sample₂ = 10/5 = 2</u>
Answer:
(a) 11.75%
(b) Profit decreases by $5.88 per calculator.
Step-by-step explanation:
(a) The percentage of failures with time is given by the following expression:
![f(x) = 0.125*e^{-0.125x}](https://tex.z-dn.net/?f=f%28x%29%20%3D%200.125%2Ae%5E%7B-0.125x%7D)
Integrating this function from x = 0 to x = 1 year, gives us the percentage of failures in the first year:
![\int\limits^1_0 {f(x)} \, dx = F(x)=-e^{-0.125x}|_0^1\\F(1) = -e^{-0.125*1}-(-e^{-0.125*0}) = 1-e^{-0.125}\\F(1) =0.1175](https://tex.z-dn.net/?f=%5Cint%5Climits%5E1_0%20%7Bf%28x%29%7D%20%5C%2C%20dx%20%3D%20F%28x%29%3D-e%5E%7B-0.125x%7D%7C_0%5E1%5C%5CF%281%29%20%3D%20-e%5E%7B-0.125%2A1%7D-%28-e%5E%7B-0.125%2A0%7D%29%20%3D%201-e%5E%7B-0.125%7D%5C%5CF%281%29%20%3D0.1175)
11.75% of the calculators will fail within the warranty period.
(b) If the cost of a calculator is $50, and the profit per sale is $25, the average revenue per calculator is $75. Considering no income in failed calculators, the new cost per calculator is:
![C =\$50*(1+0.1175)\\C=\$55.88](https://tex.z-dn.net/?f=C%20%3D%5C%2450%2A%281%2B0.1175%29%5C%5CC%3D%5C%2455.88)
The effect of warranty replacement on profit is given by the difference in cost per calculator:
![\Delta P= \$50-\$55.88=-\$5.88](https://tex.z-dn.net/?f=%5CDelta%20P%3D%20%5C%2450-%5C%2455.88%3D-%5C%245.88)
Profit decreases by $5.88 per calculator.